If you are talking about the common triangle puzzle, then there are 27 triangles. There are 16 one-cell triangles, 7 four-cell triangles, 3 nine-cell triangles, and 1 sixteen-cell triangle.
There is a link to the pic for you also.
The answer in a two dimensional way would be 27. However, if you take into account that each triangle can be turned three ways, then you can understand that there are actually 81 triangles in all.
THen you could ask the question, how many triangles can fit in this space (i.e. the picture)? The answer is the first level of infinitely many, or Aleph zero. This would be by finding the midpoint of each side of the all the 1- cell triangles and creating a new triangle.
There are 3 triangles in a pentagon
when you multiply the area of the small triangle by four it equals the area of the large triangle.
There are 2 triangles in a square so the ratio to square and triangle is 2 to 1
All Triangles add up to 180 degrees, no matter if it is Right or Scalene or ANY TRIANGLE!! If it does not, it is not a triangle!
there are 27 triangles in a triangle
Well a Sierpinski Triangle is a triangle mad up of 69 small triangles.
it have 16 triangles in a triangleOnly one.
All you have to use is the five triangles. The two large triangles make a square in the middle, the two small triangles make a large triangle on one side and the middle triangle on the other side.
Any triangle can be congruent to infinitely many triangles.
That would depend on which hexagon and what triangles. A small hexagon might not have room for any large triangles. A large hexagon will have room fro many small triangles.If you have a regular hexagon and connect the vertices you will have drawn six equilateral triangles
27 triangles. There are 16 one-cell triangles, 7 four-cell triangles, 3 nine-cell triangles, and 1 sixteen-cell triangle.
No but the sum of the squared sides will equal the square of the hypotenuse using Pythagoras' theorem for a right angle triangle
59,049 shaded triangles
Place the two large triangles next to each other so that their hypotenuses together make the long parallel side of the trapezoid. Place the medium triangle between the two large triangles with its hypotenuse along the edge of one of the large triangles. Place one of the small triangles between the medium triangle and the other large triangle with its hypotenuse along the edge of the medium triangle Place the square between the large triangle and the small triangle so that its edges are along side the small triangle and the large triangle. Finally place the parallelogram between the square and the medium triangle (toughing both) to finish the isosceles trapezoid. The seventh piece,. the final small triangle, which is not used, can be placed on top of the parallelogram (with its hypotenuse touching) to create a large triangle,. An Isosceles trapezoid can also be formed from all 7 pieces - take the large square formed by all the pieces except the two large triangles (as above if the large triangle is completed), and put the two large triangles on opposite sides to complete the isosceles trapezoid.