(12 x 11 x 10 x 9)/(4 x 3 x 2 x 1) = 11,880/24 = 495 different groups.
Three groups every time.
495/3 = 165 ways for the different groups to stand.
There are 5040 ways.
7
20*19*18*17*16 = 1860480 ways.
I Dont Know [210]
Well, honey, there are 30 students in the class, and you want to choose a group of 3. So, you're looking at a classic combination situation. The formula for combinations is nCr = n! / r!(n-r)!, so in this case, it's 30C3 = 30! / 3!(30-3)! = 4060 ways to choose those 3 lucky students. It's like picking the winning lottery numbers, but with fewer tears and more math.
they can be 2 groups of 16, 4 groups of 8, 8 groups of 4, or 16 groups of 2
To divide a class of 32 students into groups with equal numbers of students, you would need to find the factors of 32. The factors of 32 are 1, 2, 4, 8, 16, and 32. Therefore, you can divide the class into 1 group of 32 students, 2 groups of 16 students, 4 groups of 8 students, 8 groups of 4 students, 16 groups of 2 students, or 32 groups of 1 student. So, there are 6 ways to divide the class into groups with equal numbers of students.
Yes, 23 can be split into equal groups. In this case, 23 can be split into 1 group of 23, 23 groups of 1, or any other combination that results in an equal distribution of the number 23 among the groups.
2 groups of 16, 4 groups of 8, 8 groups of 4, 16 groups of 2. Not really divided or in groups, but there could be 1 group of 32 or everyone by themselves.
150
The formula would be: (40!/36!)/4! This gives 2193360/24, or 91,390 unique groups.
There are only two possibilities... 10 groups of 2 or 5 groups of 4. Unless - you can have varying sized groups - which you didn't specify.
6.4
7
One side is labled North, and the other side is labled South
There are 19 ways to do this.
There are 5040 ways.