(12 x 11 x 10 x 9)/(4 x 3 x 2 x 1) = 11,880/24 = 495 different groups.
Three groups every time.
495/3 = 165 ways for the different groups to stand.
There are 5040 ways.
7
20*19*18*17*16 = 1860480 ways.
I Dont Know [210]
6 ways. 32 divided by 1=32 32 divided by 2=16 32 divided by 4= 8 32 divided by 8 = 4 32 divided by 16= 2 32 divided by 32= 1
To divide a class of 32 students into groups with equal numbers of students, you would need to find the factors of 32. The factors of 32 are 1, 2, 4, 8, 16, and 32. Therefore, you can divide the class into 1 group of 32 students, 2 groups of 16 students, 4 groups of 8 students, 8 groups of 4 students, 16 groups of 2 students, or 32 groups of 1 student. So, there are 6 ways to divide the class into groups with equal numbers of students.
Oh, absolutely! Let's take a moment to appreciate the number 23. You can split it into equal groups, like 2 groups of 11 and 1 group of 1. Remember, there are many ways to divide numbers, so feel free to explore and find the one that brings you joy.
they can be 2 groups of 16, 4 groups of 8, 8 groups of 4, or 16 groups of 2
2 groups of 16, 4 groups of 8, 8 groups of 4, 16 groups of 2. Not really divided or in groups, but there could be 1 group of 32 or everyone by themselves.
150
The number of ways a teacher can select 5 students from a larger group depends on the total number of students available. If there are ( n ) students, the selection can be calculated using the combination formula ( C(n, 5) = \frac{n!}{5!(n-5)!} ). This formula counts the number of unique groups of 5 students that can be formed from the total. If ( n ) is specified, you can plug that value into the formula to find the exact number of ways.
The formula would be: (40!/36!)/4! This gives 2193360/24, or 91,390 unique groups.
7
There are only two possibilities... 10 groups of 2 or 5 groups of 4. Unless - you can have varying sized groups - which you didn't specify.
6.4
There are 19 ways to do this.
There are 5040 ways.