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In how many ways can 7 students line up a a ticket booth?
There are 5040 ways.
How many ways can seven students line up to buy concert tickets?
7
If there are 27 people in a class how do you work out how many different ways can they line up?
27!
How many different ways can a teacher select 5 students from a class of 19 to each perform different task?
19*18*17*16*15 = 1,395,360
In how many different ways can 5 students be arranged for a group picture if all students must face forward and be in a straight line?
For the first spot, you can choose any one of 5 students. For the second spot, you can choose any one of the remaining 4 students. For the third spot, you can choose any one of the remaining 3 students. etc. So the answer is: 5x4x3x2x1 = 120
In how many ways can 7 students line up a a ticket booth?
There are 5040 ways.
How many different ways can 1 committee of 5 students be selected from a class of 25?
53,130 ways.
Is this a permutation In how many different ways could a committee of 5 students be chosen from a class of 25 students?
6,375,600
How many ways can an adviser chosen 4 students from a class of 12 if they are given a different task?
There are 11880 ways.
How many ways can a president and vice president be randomly selected from a class of 28 students?
They can be selected in 756 ways.
How many ways can 4 students stand in line?
4*3*2*1 = 24 ways.
In a class of 5 students how many ways could they be arranged to stand in a line?
5! (5 factorial), which is 1 x 2 x 3 x 4 x 5.
4 students in a class of 12. How many ways can the students be chosen if they are each given a different task?
To determine how many ways 4 students can be chosen from a class of 12 and assigned different tasks, we first select 4 students from the 12, which can be done in ( \binom{12}{4} ) ways. Then, we can assign the 4 different tasks to these students in ( 4! ) (24) ways. Therefore, the total number of ways to choose the students and assign the tasks is ( \binom{12}{4} \times 4! = 495 \times 24 = 11,880 ).
How many ways can six students be arrange in a lunch line?
The number of ways to arrange six students in a lunch line can be calculated using the factorial of the number of students. Specifically, this is 6! (6 factorial), which equals 6 × 5 × 4 × 3 × 2 × 1 = 720. Therefore, there are 720 different ways to arrange six students in a lunch line.
How many ways can seven students line up to buy concert tickets?
7
How many ways can a teacher select 5 students from a class of 23 students to create a bulletin board display?
Well, honey, to select 5 students from a class of 23, you're looking at a good old-fashioned combination problem. So, the number of ways a teacher can select 5 students from a class of 23 is 23 choose 5, which equals 3,359 ways. So, get those students ready to shine on that bulletin board!
If there are 27 people in a class how do you work out how many different ways can they line up?
27!
