6
It would have 72 total sides, or faces. 6 per die, 12 dice, 12 x 6 = 72.
You can make $1.05 thirty one ways
There are 12 ways to arrange 5 squares however i want to know what are the ways to do that! Can anybody help me too!!
12C4= 12*11*10*9/(47*3*2*1) = 495 ways.12C4= 12*11*10*9/(47*3*2*1) = 495 ways.12C4= 12*11*10*9/(47*3*2*1) = 495 ways.12C4= 12*11*10*9/(47*3*2*1) = 495 ways.
(12 x 11 x 10 x 9)/(4 x 3 x 2 x 1) = 11,880/24 = 495 different groups.Three groups every time.495/3 = 165 ways for the different groups to stand.
12
The answer depends on how many dice are rolled. With 12 or more dice, the answer is 0.The answer depends on how many dice are rolled. With 12 or more dice, the answer is 0.The answer depends on how many dice are rolled. With 12 or more dice, the answer is 0.The answer depends on how many dice are rolled. With 12 or more dice, the answer is 0.
To find the number of ways to make a total of 12 with 4 six-sided dice, you can use combinatorial methods or generating functions. The total number of combinations that yield 12 can be calculated as the number of non-negative integer solutions to the equation (x_1 + x_2 + x_3 + x_4 = 12) with the constraint that (1 \leq x_i \leq 6) for each die. After performing the calculations, there are 25 distinct combinations to achieve a sum of 12 with 4 dice.
A die had 12 edges. The number of edges that dice have will depend on the number of dice!
There are a total of 12 faces on a pair of dice.
there are many answers. you need to know how many sides are on the dice
230
4
The sums divisible by 3 are 3, 6, 9 and 12. These can be obtained in 2, 5, 4 and 1 ways respectively, giving 2 + 5 + 4 + 1 = 12 ways of success. There are 36 possible ways two dice can fall → probability = ways_of_success/possible_ways = 12/36 = 1/3.
12 ways.
A cube has 6 faces, 8 vertices's, and 12 edges.The dice is similar to a cube, as the dice has the same number of vertices as a cube.
It would be 5 ways