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How much would 900 invested at 6 percent interest compounded continuously be worth after 4 years?
At 6% interest, the total amount of money increases by a factor of 1.06 (100% + 6%) every year, so to get the amount after 4 years, you calculate 900 x 1.064.
800 dollars invested at an annually compounded interest rate of 6 percent will be worth how much at the end of 10 years?
The equation is P=C(1+r)^t; where C is the money invested, r is the rate(change from percent to decimal form), and t is the time. So plug in the numbers to get: P=800(1+.06)^10 The answer is 1432.678, I would round it to $1432.68
If you have 2500 to invest at 6 interest compounded quarterly. For how many years will the money need to be invested for that amount to triple?
It will take 19 years.
What is the present value of 2000 discounted back three years if the interest rate is 8 percent compounded monthly?
If a sum of money was invested 36 months ago at 8% annual compounded monthly,and it amounts to $2,000 today, thenP x ( 1 + [ 2/3% ] )36 = 2,000P = 2,000 / ( 1 + [ 2/3% ] )36 = 1,574.51
How much would 300 invested at 7 interest compounded continuously be worth after 4 years Round your answer to the nearest cent. Do not include units in your answer.?
7% compound interest means that the amount of money increases, every year, by a factor of 1.07. After 4 years, you have 300 x 1.07^4.
How much money has to be invested at 5.1 percent interest compounded continuously to have 17000 after 14 years?
Type your answer here... $8,324.59
How much money has to be invested at 4.3 percent interest compounded continuously to have 19000 dollars after 16 years?
You would need 9687 dollars.
How much money invested at 10 percent compounded continuously for 3 years will yield 630?
630/(1.1)3 = 630/1.331 = 473.33
How long will it take for an amount of money invested at an annual rate of 5.75 percent compounded continuously to triple in value?
y = ln(3)/ln(1.0575) = 19.65 years, approx.
How much money should be invested at 14 percent compounded quarterly to yield 12000 at the end of 7 years?
4795.65 (approx).
How much money must be deposited today to become 2450 in 20 years at 8.5 compounded continuously?
479.26 needs to be invested to get to 2450 after 20 years at 8.5% compound interest.
How much would 900 invested at 6 percent interest compounded continuously be worth after 4 years?
At 6% interest, the total amount of money increases by a factor of 1.06 (100% + 6%) every year, so to get the amount after 4 years, you calculate 900 x 1.064.
A sum of money invested at 4 percent interest compounded semiannually will double in amount in aprproximately how many years?
I haven't gotten the answer to that test question either....the choices seem wrong
How long will it take for money to double in a savings account that is compounded continuously?
Five years
How much money will there be in an account at the end of 4 years if 11000 is deposited at a 4.5 percent annual rate that is compounded continuously?
11000*(1.045)^4=$13117.70stop cheating on your math homework
Matt places 1200 in an investment account earning an annual rate of 6.5 percent compounded continuously Determine the amount of money that Matt will have in account after 10 years?
Matt will have $2,298.65.
How much money has to be invested at 2.3 interest compounded continuously to have 41000 after 17 years?
To find the amount to be invested (P) at a continuously compounded interest rate of 2.3% to reach $41,000 in 17 years, we use the formula ( A = Pe^{rt} ), where ( A ) is the amount, ( r ) is the interest rate, and ( t ) is the time in years. Rearranging the formula to solve for P gives us ( P = \frac{A}{e^{rt}} ). Plugging in the values: ( P = \frac{41000}{e^{0.023 \times 17}} ). Calculating this yields approximately $19,153.77.
