Compound Interest = P(1+r/100n)(nt)
P = Original Investment
r = Interest Rate
n = How often the interest is compounded per year
t = Number of years
Interest = 200(1+6/100)6
= 200(1.06)6
=$283.70
500 invested for 5 years at 7% interest compounded annually becomes 701.28
396.93
Inserting values into the formula for compound interest, you get:4100 * (1 + 3.75/100) to the power 6.
If 1500 dollars is invested at an interest rate of 3.5 percent per year compounded continuously, after 3 years it's worth $1666.07, after 6 years it's $1850.52, and after 18 years it's worth $2816.42.
The equation is P=C(1+r)^t; where C is the money invested, r is the rate(change from percent to decimal form), and t is the time. So plug in the numbers to get: P=800(1+.06)^10 The answer is 1432.678, I would round it to $1432.68
How much would $500 invested at 9% interest compounded annually be worth after 4 years? 705.79
500 invested for 5 years at 7% interest compounded annually becomes 701.28
320.71
267.65
$428.24
280.51
814.45
1006.1
655.40
1095.91
If the interest is compounded annually, then the first interest payment isn't added until the end of the first year. Until then, the investment is worth exactly $15,000.00 .
$280.51