I want to write a algebraic expression Anita scored 37 points on 2 point 3 point goals she scored 6 more 2 pointers than 3 pointers How many of each did she score?

Answer 1

Let's denote the number of 2-point goals Anita scored as x, and the number of 3-point goals she scored as y. We can create the following system of equations based on the information given:

1. 2x + 3y = 37 (Total points scored)
2. x = y + 6 (She scored 6 more 2-pointers than 3-pointers) By substituting the second equation into the first equation, we get: 2(y + 6) + 3y = 37. Solving this equation, we find that y = 5 and x = 11. Therefore, Anita scored 11 two-point goals and 5 three-point goals.

Answer 2

this is how I would do it (substitution). there are other methods. let number of 2 point goals be x and number of 3 point goals be y 2x + 3y = 37 (1) x = y + 6 (2) substitute x = y + 6 into (1) 2(y+6) + 3y = 37 2y + 12 + 3y = 37 5y = 25 y = 5 substitute y = 5 into (2) x = 5 + 6 x = 11 substitute x = 11 and y = 5 into (1) 2(11) + 3(5) = 37 22 + 15 = 37 hope this helps not sure if its quite what you need.