It is a quadratic expression which when factored is (2y+3)(y+5)
To simplify Y plus Y, you can combine the like terms. In this case, both Y terms are like terms because they have the same variable. When you add them together, you get 2Y. Therefore, Y plus Y simplifies to 2Y.
how do u identify a independent variable
Like terms have the same variable, but can have different constants. 8y : variable is y, constant is 8 y: variable is y, constant is 1 (but this doesn't need to be shown) So yes, theses are like terms.
If I understand the question correctly, and that is by no means certain, then x = (y-1)/2
'y' is a variable. '15' is not. [ y+15 ] is an expression in one variable.
In the expression y+15, there is one variable, the "y."
It is a quadratic expression which when factored is (2y+3)(y+5)
4y + 9The variable is Y. The variable is the letter (the unknown amount)
An unknown variable.
y is the variable
In the expression 5 + y + 8, y is a variable. We know how much 5 and 8 are, those are definite quantities. Only y has an unknown, and hence variable value.
It is a variable which can take any value.
No.No.No.No.
A dependant variable is a term used in science to identify the response that is measured in an experiment. When a researcher conducts an experiment, he is interested in the outcome, defined as the dependent variable.
y=a+bx so the slope is b
-15