7,9,10,11,13 Assume the data list from smallest to largest is A,B,C,D,E. Then from the info given C=10 since 10 is the median. Also the range of the data is 6, so that means that E-A = 6. Since the mean of the data is 10 then (A+B+C+D+E)/5 = 10 or A+B+C+D+E = 50 You can substitute the value for C and E = 6+A (since the range is 6) to get A+B+10+D+(6+A) = 50 or simplified: 2A + B + D =34 Now since the median of the data is 10 the value of B will be less than 10 and A will be less than B. The value of D will be greater than 10 and E will be greater than D. To figure out the data list use trial and error. Start by picking a value of D > 10. Start with 11. From the equation above you have 2A + B + 11 = 34, now pick a value of B < 10. Start with 9 and substitute to solve for A. 2A + 9 + 11 = 34 or 2A = 14 and A=7 So A=7, B=9, C=10, D=11 and E=6+A or 13. To check see if these numbers equal the mean of 50. (7+9+10+11+13)/5 and it does. If it didn't work then you'd have to go back and pick values of B, D again until it does. Hope that helps.
Yes. If the predominant data are higher than the median, the mean average will be higher than the median average. For example, the median average of the numbers one through ten is five. The mean average is five and one-half.
Because the mode is 5, we know at least two of the numbers are 5. Because the median is 12 and we have five numbers, we know one of them is 12. Because the range is 10 and the smallest number we know so far is 5, we'll try 15 for a fourth number. This gives us: 5, 5, 12, 15 The mean is 10, so we know the sum of all five numbers is 50. The sum of the four numbers we have so far is 5+5+12+15 = 37. Thus, the fifth number is 50-37 = 13. That gives us 5, 5, 12, 13, 15. These five numbers fit all the criteria.
If the mean is 6 then the 5 numbers must total 6 * 5 = 30. Median is 7, so that leaves 4 numbers totaling 23. So we need 2 numbers less than (or equal to) 7 and 2 numbers greater than (or equal to) 7 which all add up to 23 and where the highest number minus the lowest number equals 10. So how about, 1,2,7,9,11 or 1,1,7,10,11 etc
1,1,2,3,43. Any set of 5 numbers such that their sum is 50 and when ordered, the middle (ie third) number is 2.
Mean is the average of all numbers.Median is the middle value.Range is the difference between the largest and smallest values.For example: You are given five numbers: 2, 4, 6, 8, 10Mean: 2 + 4 + 6 + 8 + 10 = (30)/5 = 6Median: 6Range: 10 - 2 = 8
What Five Numbers have a range of 5 a median of 16 and a mean of 15
4 4 6 6 10
2 4 4 6 8
44689
Median is only meaningful with a set of data. The median of five would just be five. Similar to asking what the average of 5 is.
5, 5, 8, 10, 12.
3, 4, 5, 6, 7, 8, and 9.
(4, 4, 6, 10, 12)
Yes. If the predominant data are higher than the median, the mean average will be higher than the median average. For example, the median average of the numbers one through ten is five. The mean average is five and one-half.
A Five number summary is the minimum, quartile 1, median, quartile 3, and maximum of the data. (numbers)
5, 6, 9, 10, & 10
3, 3, 5, 9, 10