There can be any number of sets to satisfy this. The median is the number in the middle and the mean is the average of the numbers. 2,4,6,8,30 is one possible set median = 6 mean = 10
6 is the median of 10 numbers
1,1,10,11,12
Because the mode is 5, we know at least two of the numbers are 5. Because the median is 12 and we have five numbers, we know one of them is 12. Because the range is 10 and the smallest number we know so far is 5, we'll try 15 for a fourth number. This gives us: 5, 5, 12, 15 The mean is 10, so we know the sum of all five numbers is 50. The sum of the four numbers we have so far is 5+5+12+15 = 37. Thus, the fifth number is 50-37 = 13. That gives us 5, 5, 12, 13, 15. These five numbers fit all the criteria.
If the mean is 6 then the 5 numbers must total 6 * 5 = 30. Median is 7, so that leaves 4 numbers totaling 23. So we need 2 numbers less than (or equal to) 7 and 2 numbers greater than (or equal to) 7 which all add up to 23 and where the highest number minus the lowest number equals 10. So how about, 1,2,7,9,11 or 1,1,7,10,11 etc
5, 6, 9, 10, & 10
4 4 6 6 10
3, 3, 5, 9, 10
There can be any number of sets to satisfy this. The median is the number in the middle and the mean is the average of the numbers. 2,4,6,8,30 is one possible set median = 6 mean = 10
8, 9, 11 and 12
The mean is 6.6. The median is 6. There is no mode.
6 is the median of 10 numbers
1,1,10,11,12
The median of the four numbers is 10.
The median is the middle number of a set when they are in order, least to greatest. If there is an even number of values, the median is the average of the middle two. Ex. 10, 17, 20, 45, 68 The median is 20. The mean is the average, which is the total of the numbers divided by how many numbers there are. Ex. 10, 17, 20, 45, 68 68 + 45 + 20 + 17 + 10 = 160 There are 5 numbers in this set. 160/5 = 32 The mean is 32.
5, 5, 8, 10, 12.
(0, 2, 15, 16, 17) 0+2+15+16+17 = 50 50/5 = 10 The median is 15, the mean is 10.