Assuming the shadows are measured at the same time of day and that the trees are on level ground, the tree with a 20-foot shadow is a quarter longer than the tree with a 16-foot shadow. Adding a quarter of the height to 12 feet makes it 15 feet tall.
Alternatively use the tangent ratio which will be opposite (height of 1st tree) over adjacent (its shadow) and multiply it by the adjacent of the 2nd tree:
(12/16)*20 = 15 feet tall.
The ratios are in the same proportion, so all you need to really figure out is what is in the same ratio to 20 as 6 is to 4.
488 cm
h = height of tree 150 / 20 = h / 2 h = (150/20) X 2 h = ? (you figure it out)
Ratio of object to its shadow is the same. So if T is the height of the tree, then T/21 = 4/6 So T = 21*4/6 = 84/6 = 14 feet
The tree is 33 feet tall. Use ratios to solve this equation. 6/4 = n/22 6 x 22 = 4n 4n = 132 n = 33
25 feet tall
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
6 feet
36.0 feet
A 1 foot shadow I think.
It is 90 feet in height
The tree is 34.5 feet tall because tangent ratio of 34.5/24 = 5.75/4
The man is twice as high as his shadow. Therefore, the tree must also be twice as high as its shadow, which would make the tree 40 feet tall.
The ratios are in the same proportion, so all you need to really figure out is what is in the same ratio to 20 as 6 is to 4.
The tree is 25 feet tall. A 5 foot pole cast a 2 foot shadow. This means that the sun angle causes the shadow to be 2/5 the length of the object casting it. The tree's shadow is 10 feet tall. Multiply 10 feet by 5/2 (inverting the fraction because we're going the other way) and we get 25 feet.
15 feet high
39