The tree is 33 feet tall.
Use ratios to solve this equation.
6/4 = n/22
6 x 22 = 4n
4n = 132
n = 33
27.3 feet
488 cm
Designate the unknown shadow length by s. Shadows cast at the same time and place are proportional to the height of the object casing the shadow. Therefore: 4/6 = s/21, or s = [4(21)]/6 = 14 feet.
The flag pole would be 20 feet. (You can see that the shadows are twice as long.) At a given time of the day, the length of a shadow cast by any object will have the same relationship to its actual height as all other objects. Here the ratio is 5/10 = x/40 and multiplying both sides by 40, 20 = x.
25
15 feet high
121.3yd
x/85 = 6/17 30 ft.
27.3 feet
48
13.5 feet Use trigonometry and the tangent ratio: 13.5/9 = 6/4
17.45 feet.
48
It works out as 12 feet and 4 inches in height
10.'384615' (recurring decimals) feet
488 cm
The lenght of the shadow will be 12.6 ft