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So in this case, what you want to do is substitute in the value of 5 everywhere there is an x in the function.

Since:

f(x) = 3x + 2

And we know what x equals (5), You would solve for f(5) with:

f(5) = 3(5) + 2

f(5) = 15 + 2

f(5) = 17

So y = 17. (Remember that f(x) is another notation for y)

So, since x = 5, and y = 17, the ordered pair is: (5, 17)

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Q: If f(x) 3x plus 2 find f(5) and give the ordered pair?
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