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Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1
3x-8y=-1 -2x+6y=1
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y = x - 7 x + y = 5 Substituting for y in the second equation, x + (x - 7) = 5 or 2x = 12 so that x = 6 Then, from the first equation, y = 6 - 7 = -1 So, (x, y) = (6, -1)
(0,7)
Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1
with ur partner
It works out that x = 6 and y = 3 or as (6, 3)
Do you mean: 4x+7y = 47 and 5x-4y = -5 Then the solutions to the simultaneous equations are: x = 3 and y = 5
3x-8y=-1 -2x+6y=1
y=3x-4 y=-2x+1
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
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3x+y = 10 y = x-2 Substitute the value of y into the top equation: 3x+x-2 = 10 => 4x = 10+2 => 4x = 12 => x = 3 Substitute the value of x into the original equations to find the value of y: So: x = 3 and y = 1
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
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