I am pretty sure they would be considered supplimentry angles. m<1+m<2=180 : definition of supplimentry
X = 180 - Y so 180 - Y = 2x + 4 and Y = 4x + 20 so 180 - 4x - 20 = 2x + 4 therefore 6x = 156 so x = 26 making Angle X = 56o and Angle Y = 124o
In parallelogram ABCD, angle A and angle D are adjacent or consecutive angles and are supplementary, meaning the sum of their measures is equal to 180 degrees. Angles A and C are opposite angles and have the same measure. These are some important properties of parallelograms. So to find the measure of angle C, you first have to find the measure of angle A. You can do that with a little algebra. First, set the expressions for the measures of angles A and D equal to 180 and solve for x. Then plug that value for x into the expression for the measure of angle A, which is the same as the measure for angle C. 5x + 30 + x = 180 6x + 30 = 180 6x = 150 x = 25 Therefore, 5x + 30 = 5(25) + 30 = 125 + 30 = 155 The measure of angle C is 155.
No way to answer this until we know either the value of 'X', or else something about the drawing.
100+80, 99+81, 98+82....
That totals 180.
The angles are supplementary if they have a sum of 180 degrees.
acute
The angle addition postulate states that if a point lies inside an angle, the sum of the two smaller angles formed is equal to the measure of the larger angle. In other words, if point B is located within angle AOC, then the measure of angle AOB plus the measure of angle BOC equals the measure of angle AOC. This postulate is fundamental in geometry for solving problems related to angles.
Complementary.
X = 180 - Y so 180 - Y = 2x + 4 and Y = 4x + 20 so 180 - 4x - 20 = 2x + 4 therefore 6x = 156 so x = 26 making Angle X = 56o and Angle Y = 124o
In parallelogram ABCD, angle A and angle D are adjacent or consecutive angles and are supplementary, meaning the sum of their measures is equal to 180 degrees. Angles A and C are opposite angles and have the same measure. These are some important properties of parallelograms. So to find the measure of angle C, you first have to find the measure of angle A. You can do that with a little algebra. First, set the expressions for the measures of angles A and D equal to 180 and solve for x. Then plug that value for x into the expression for the measure of angle A, which is the same as the measure for angle C. 5x + 30 + x = 180 6x + 30 = 180 6x = 150 x = 25 Therefore, 5x + 30 = 5(25) + 30 = 125 + 30 = 155 The measure of angle C is 155.
120 Since the measures of the angles of supplementary angles add up to 180, 60 plus something else equals 180. 180-60=120
Yes, a quadrilateral ABCD can be a parallelogram if angle D plus angle B equals 180 degrees. In a parallelogram, opposite angles are equal, and consecutive angles are supplementary (their sum equals 180 degrees). Therefore, if angle D and angle B are supplementary, it is consistent with the properties of a parallelogram. Thus, the condition does not contradict the definition of a parallelogram.
if angle 1 puls angle 5 ewuals 100 find the measure of angle 3
If measure angle 3 = x2 + 4x and measure angle 5 = 3x + 72, find the possible measures of angle 3 and angle 5
Angle a plus angle b subtract from 180 equals angle c
The measure of angle b would depend on the sum of the angles a and b which has not been given so therefore a solution is not possible.