I am pretty sure they would be considered supplimentry angles. m<1+m<2=180 : definition of supplimentry
X = 180 - Y so 180 - Y = 2x + 4 and Y = 4x + 20 so 180 - 4x - 20 = 2x + 4 therefore 6x = 156 so x = 26 making Angle X = 56o and Angle Y = 124o
In parallelogram ABCD, angle A and angle D are adjacent or consecutive angles and are supplementary, meaning the sum of their measures is equal to 180 degrees. Angles A and C are opposite angles and have the same measure. These are some important properties of parallelograms. So to find the measure of angle C, you first have to find the measure of angle A. You can do that with a little algebra. First, set the expressions for the measures of angles A and D equal to 180 and solve for x. Then plug that value for x into the expression for the measure of angle A, which is the same as the measure for angle C. 5x + 30 + x = 180 6x + 30 = 180 6x = 150 x = 25 Therefore, 5x + 30 = 5(25) + 30 = 125 + 30 = 155 The measure of angle C is 155.
No way to answer this until we know either the value of 'X', or else something about the drawing.
That totals 180.
The four interior angles in a quadrilateral always equal 360 degrees when added together. So, 110 plus 70 plus 110 equals 290. Therefore, the answer is 70 degrees.
The angles are supplementary if they have a sum of 180 degrees.
acute
Complementary.
Either can be greater, depending on the exact angles involved.
X = 180 - Y so 180 - Y = 2x + 4 and Y = 4x + 20 so 180 - 4x - 20 = 2x + 4 therefore 6x = 156 so x = 26 making Angle X = 56o and Angle Y = 124o
In parallelogram ABCD, angle A and angle D are adjacent or consecutive angles and are supplementary, meaning the sum of their measures is equal to 180 degrees. Angles A and C are opposite angles and have the same measure. These are some important properties of parallelograms. So to find the measure of angle C, you first have to find the measure of angle A. You can do that with a little algebra. First, set the expressions for the measures of angles A and D equal to 180 and solve for x. Then plug that value for x into the expression for the measure of angle A, which is the same as the measure for angle C. 5x + 30 + x = 180 6x + 30 = 180 6x = 150 x = 25 Therefore, 5x + 30 = 5(25) + 30 = 125 + 30 = 155 The measure of angle C is 155.
120 Since the measures of the angles of supplementary angles add up to 180, 60 plus something else equals 180. 180-60=120
if angle 1 puls angle 5 ewuals 100 find the measure of angle 3
If measure angle 3 = x2 + 4x and measure angle 5 = 3x + 72, find the possible measures of angle 3 and angle 5
Angle a plus angle b subtract from 180 equals angle c
The measure of angle b would depend on the sum of the angles a and b which has not been given so therefore a solution is not possible.
cheater