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Corinda has 400 feet of fencing to make a play area She wants the fenced area to be rectangular What dimensions should she use in order to enclose the maximum possible area?
I got no clue.
What is the total length in yards of fencing needed to enclose a rectangular area 1152 feet by 96 feet?
832 yards
A rectangular field is to be enclosed with 1180 ft of fencing If the length of the field is 50 ft longer than the width then how wide is the field?
Length = x+50. Width = x 2(x+50+x) = 1180 2x+100+2x = 1180 4x = 1180-100 4x = 1080 x = 270 Width = 270 feet
Sohan built a rectangular pen for his sheep with an area of 242 square feet He only had 66 feet of fencing to use He wanted the length to be twice as long as the width What were the dimensions of the?
Let the length be 2x and the width be x: 2(2x+x) = 66 the perimeter in feet 4x+2x = 66 6x = 66 x = 11 Therfore: length = 22 feet, width = 11 feet and 22*11 = 242 square feet.
What is the equation for fencing?
Number of fencing panels required = Roundup(Length of fencing required/Panel length) There is no information in the question about the area to be fenced, so there is no simple formula to calculate the length of fencing required. It is assumed that the fencing panels used are all of the same length.
Corinda has 400 feet of fencing to make a play area She wants the fenced area to be rectangular What dimensions should she use in order to enclose the maximum possible area?
I got no clue.
If you have 400ft of fencing and you want the fencing to be a rectangle area what dimensions in order to enclose the maximum possible area?
100 x 100
A rectangular field was fenced and divided into three parts as shown by hines in the figure the dimensions are given toohow many meters of fencing materials are used please answer it?
To determine the amount of fencing materials used for a rectangular field divided into three parts, you need to calculate the perimeter of the entire rectangular field and the additional fencing used for the divisions. If the dimensions of the rectangle are provided, you can use the formula for the perimeter (P = 2(length + width)) and then add the lengths of the dividing fences. Without specific dimensions, I can't provide a numerical answer, but you can apply this approach using the given measurements.
What is the number of poles needed when fencing a rectangular garden?
The answer depends on the dimensions of the garden as well as how wide the fence panels are. Without the information, it is pointless to try and answer the question.
What are all possible dimension of a rectangular garden that you could make using 40 feet of the fencing in one-foot lengths?
To find the possible dimensions of a rectangular garden using 40 feet of fencing, we can use the formula for the perimeter of a rectangle: ( P = 2 \times (length + width) ). Setting the perimeter to 40 feet gives us the equation ( length + width = 20 ). Therefore, for any integer value of the length (from 1 to 19 feet), the width can be calculated as ( width = 20 - length ). Possible pairs of dimensions include (1, 19), (2, 18), (3, 17), and so on, up to (19, 1).
The largest rectangular fencing you can make with 56ft of fencing?
A square 14 ft on a side.
If you have 16m of fencing to put in your rectangular garden what dimensions might your garden be?
long side= 5 short= 3 long = 7 short = 1 long= 6 short= 2
How can you find the diameter of a circular fiel that can be enclosed in a certain length of fencing materials?
Divide the length of the fencing by pi.
What is the largest rectangular area that can be enclosed with 400 feet of fencing What are the dimensions of the rectangle -- Quadratic Modeling?
Find the dimensions of the rectangular field of maximum area which can be enclosed with 400 feet of fence. . Let w = width of field then (400-2w)/2 = length of field (200-w) = length of field . area = w(200-w) area = 200w-w^2 area = -w^2+200w . Looking at the coefficient for the w^2 term, we see that it is negative. This indicates that the parabola opens downward and finding the vertex will give you the "maximum". . Standard vertex form is: y= a(x-h)^2+k where (h,k) is the vertex . Convert our equation into that form by "completing the square": area = -w^2+200w area = -(w^2-200w) area = -(w^2-200w+10000) + 10000 area = -(w-100)^2 + 10000 . From the above, we see that the vertex is: (h,k) = (100, 10000) . This says that when the width=100 feet, the area will be maximized at 10000 square feet. . Solution: width = 100 feet length = 200-w = 200-100 = 100 feet
How many sides of fencing are needed to make a rectangular enclosure?
4
A dog owner has 200 ft of fencing and wants to enclose the greatest possible rectangular area for her dog what demension should she use?
50' x 50'and its spelled dimension not demension
Mary wants to build a fence around her rectangular garden Its 10m wide and 15m longHow much fencing does she need to buy?
As the rectangular garden is 10m wide, then two sides will require 10m of fencing. Thus 2*10 = 20m of fencing. It is also 15m long, so two sides will require 15m of fencing. Thus 2*15 = 30m of fencing. Adding up all 4 sides => 20+30 = 50m of fencing.
