4 x 4
I got no clue.
832 yards
Length = x+50. Width = x 2(x+50+x) = 1180 2x+100+2x = 1180 4x = 1180-100 4x = 1080 x = 270 Width = 270 feet
Let the length be 2x and the width be x: 2(2x+x) = 66 the perimeter in feet 4x+2x = 66 6x = 66 x = 11 Therfore: length = 22 feet, width = 11 feet and 22*11 = 242 square feet.
Number of fencing panels required = Roundup(Length of fencing required/Panel length) There is no information in the question about the area to be fenced, so there is no simple formula to calculate the length of fencing required. It is assumed that the fencing panels used are all of the same length.
I got no clue.
100 x 100
The answer depends on the dimensions of the garden as well as how wide the fence panels are. Without the information, it is pointless to try and answer the question.
A square 14 ft on a side.
long side= 5 short= 3 long = 7 short = 1 long= 6 short= 2
Divide the length of the fencing by pi.
4
50' x 50'and its spelled dimension not demension
As the rectangular garden is 10m wide, then two sides will require 10m of fencing. Thus 2*10 = 20m of fencing. It is also 15m long, so two sides will require 15m of fencing. Thus 2*15 = 30m of fencing. Adding up all 4 sides => 20+30 = 50m of fencing.
The long rectangular strip is called a piste.
1974/3.14=628.66 meters
The perimeter of the rectangular field is 2*(L+W) = 2*(120+50) = 2*170 = 340 feet