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If the average of three distinct integers is 37 and the least integer is 18 .what could be the greatest integer?
Wiki User
∙ 6y ago
Solving for the third integer:
(a + b + c) / 3 = 37 (by the definition of "average")(18 + b + c) / 3 = 37 (assuming "a" is the least integer)
18 + b + c = 111
c = 111 - 18 - b (solving for the third integer)
c = 93 - b
Now, "b" must be at least 18, in which case:
c = 93 - 18 = 75
On the other hand, the largest "b" can be is when it is equal to "c" (since I am assuming that "c" is the largest integer):
c = 93 - b
c = 93 - c
2c = 93
c = 46.5
Adjusting the numbers a bit (since we need integers), in this case we get the numbers 18, 46, 47
Thus, the greatest integer can be anything in the range from 47 to 75.
Wiki User
∙ 6y ago
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