The answer depends on what AB is and, since you cannot be bothered to provide that information, I cannot give a sensible answer.
circumference of the circle = 2*pi*10 = 20pi units of measurement length of arc = (120/360)*20pi = 20.944 units (rounded to 3 decimal places)
Using the distance formula the length of ab is 5 units
96 TM!!!
Suppose ABC is a triangle. There is nothing in the question that requires the triangle to be right angled. Suppose AB is the side opposite to angle C and BC is a side adjacent to angle C. Then AB/BC = sin(C)/sin(A)
If you mean endpoints (-1, -3) and (11, -8) then by using the distance formula the length between the points is 13 units
length work
All you've told us is that 40 cm is less than 1/2 of the circumference. With that information, all we know is that the circumference is more than 80 cm. We could calculate it if we knew what the angle is at the center of circle between the two radii (radiuses) that go to the ends of arc AB. We're guessing that it's there in your book, but you forgot to include it when you decided to ask us to do your homework problem for you.
In order to answer that question, we'd need to see the drawing, and find out how 'ab' is related to the circle.
3.82 units
circumference of the circle = 2*pi*10 = 20pi units of measurement length of arc = (120/360)*20pi = 20.944 units (rounded to 3 decimal places)
exactly three times as far from point A as they are from point B?
The area of the whole circle is PI x 6 squared which equals 36 PI. We can now use the ratio 30/36 = x/360 to find the angle (360 is the full angle if the circle, x is the angle of the segment, pi's cancell out) If we solve for x we get 300 degrees which is the angle we need. As for the length, the circles circumference is 12 PI (12 is the diameter). This means that 30/36= AB/12PI AB=10PI
Arc AB represents 40/240 = 1/6 of the circumference of the circle. As the angle at the centre subtended by the whole circle is 360° then ∠A0B (if the center is O) measures 1/6 x 360 = 60°. Since a central angle has the same number of degrees as the arc it intercepts, the arc ACB (note we can call the arc AB as arc ACB) measures 60°.
6.8 cm
This is your lucky day ! Watch now, as the Great and Powerful WA Contributorsolves your problem and answers your question without ever seeing the drawingthat's supposed to go along with it, and with no idea what 'BC' and 'ab' are . . .-- A whole circle has a central angle of 360 degrees.-- A whole circle with a radius of 10 has a circumference of [ (2 pi) x (radius) ] = 20 pi .-- A slice of cake with a central angle of 120 degrees is 1/3 of a circle.-- The arc at the fat end of the slice is 1/3 of the full circle's circumference = 20 pi/3 = 20.944 (rounded)-- Just in case 'BC' is the long arc, then its length is the other 2/3 of the whole circle= 2 x 20 pi/3 = 41.888 (rounded)Pay no attention to that old man behind the curtain.
Length AB is 17 units
12