Using the distance formula the length of ab is 5 units
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1/3 + 1/4? 1/3 can be changed to 4/12.. 1/4 can be changed to 3/12.. 3/12 + 4/12 = 7/12 you can't simplify 7/12, so your final answer is 7/12.
Convert to the same units, then the units can be dropped and the ratio simplified: 1 ft = 12 inches → 9 in : 7 ft = 9 in : 7 × 12 in = 9 : 7 × 12 = 3 × 3 : 7 × 4 × 3 = 3 : 7 × 4 = 3 : 28
The perimeter of a rectangle is 2length +2 width. the width is x the length is x+4. Plug into the equation 2(x)+2 (x+4)=20 2x+2x+8=20 4x=12 x=3 The width is 3 the length is 7 (3+4) Area is length times width. 3(7)= 21. the area is 21 centimeters
7/12 divided by 2/3 equal 7/12 times 3/2 (We invert and multiply when dividing fractions.) 7/12 times 3/2 equals 7 x 3 / 12 x 2 (Multiply the numerators together and multiply the denominators together.) 7 x 3 / 12 x 2 = 21 / 24 Now find the lowest common denominator. 21 / 24 = 7 / 8
Using the distance formula the length of ab is 5 units
5 [3-4-5 triangle]
5 [3-4-5 triangle]
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
We suspect that 'A' is not equal to 7 9, but that (7, 9) arethe coordinates of 'A'. Same for 'B'.If that's true, then the two points are 5 units apart.
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twelve -------------------- The original rectangle is 12 feet in length and 5 feet in width. The length (12) is 7 feet greater than the width (5 feet). Were the length decreased by 3 (12 - 3 = 9) and the width increased by 2 (5 + 2 = 7), the perimeter would be 32 feet (9 + 7 + 9 + 7 = 32).
7 inches
By unit of length and distance and conversion ,we can say that 1 feet =12 in 3 feet =36 in 3 ft 7 in =43 in
Area = Length * Width = 12*7 = 84 square inches.
Ex: 3/a + 4/b = 7, LCD is ab ab x (3/a) + ab x (4/b) = ab x 7 3b + 4a = 7ab so that the denominators have cancelled. a and b can represent binomials, monomials, polynomials, etc. EX: 3/(x+2) + 4/(x-5) = 7 multiply by ab = (x+2)(x-5)