The values that make each of the factors zero. In other words, you need to solve:x - 2 = 0
and:
x - 5 = 0
-2.5 + 1.6583123951777i-2.5 - 1.6583123951777i
the zeros of a function is/are the values of the variables in the function that makes/make the function zero. for example: In f(x) = x2 -7x + 10, the zeros of the function are 2 and 5 because these will make the function zero.
1+x2 is a polynomial and doesn't have a real root.
x=11+69/2 and x=11-69/2
There are none because the discriminant of the given quadratic expression is less than zero.
x2 + 6x - 27 = (x + 9)(x - 3)
Not quite. The polynomial's linear factors are related - not equal to - the places where the graph meets the x-axis. For example, the polynomial x2 - 5x + 6, in factored form, is (x - 2) (x - 3). In this case, +2 and +3 are "zeroes" of the polynomial, i.e., the graph crosses the x-axis. That is, in an x-y graph, y = 0.
x2+5x-14 = (x+7)(x-2) when factored
Restate the question: Factor the polynomial x2 + 7x + 10. You look for two numbers which multiply to make 10 and add to make 7. They are 5 and 2. Now put them into the two factors: (x + 5)(x + 2). Check your factors by multiplying using 'FOIL': x2 + 2x + 5x + 10 = x2 + 7x + 10. Check!
(x + 1) and (x + 2) are monomial factors of the polynomial x2 + 3x + 2 (x + 1) and (x + 3) are monomial factors of the polynomial x2 + 4x + 3 (x + 1) is a common monomial factor of the polynomials x2 + 3x + 2 and x2 + 4x + 3
(x+7) and (x-3)
(x+8)(x-3)
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.
It is (x+9(x-2) when factored
-2.5 + 1.6583123951777i-2.5 - 1.6583123951777i
X2 - 6X + 27 = 0 what are the factors of 27 that add to - 6? None! This polynomial is unreal and does not intersect the X axis.
Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.