x=11+69/2 and x=11-69/2
-2.5 + 1.6583123951777i-2.5 - 1.6583123951777i
There are none because the discriminant of the given quadratic expression is less than zero.
x2 + 3x - 5 is an expression, not an equation. An equation may have roots, an expression does not. However, x2 + 3x - 5 = 0 is an equation and its roots are -4.1926 and 1.1926 (approx).
A fifth degree polynomial.
Using the discriminant the possible values of k are -9 or 9
-2.5 + 1.6583123951777i-2.5 - 1.6583123951777i
There are none because the discriminant of the given quadratic expression is less than zero.
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
x = -2.5 + 1.6583123951777ix = -2.5 - 1.6583123951777iwhere i is the square root of negative one.
1
-2 and -6
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
None, it involves the square root of a negative number so the roots are imaginary.
To find the roots of the polynomial (x^2 + 5x + 9), we can use the quadratic formula: (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}). Here, (a = 1), (b = 5), and (c = 9). The discriminant (b^2 - 4ac = 5^2 - 4 \cdot 1 \cdot 9 = 25 - 36 = -11), which is negative. This means the polynomial has no real roots, but two complex roots: (x = \frac{-5 \pm i\sqrt{11}}{2}).
-6 Check: -6+4-6+8 = 0
The expression (4x^2 + 16x + 15) is a quadratic polynomial. It can be factored into ((2x + 3)(2x + 5)). Alternatively, it can be analyzed using the quadratic formula to find its roots or solved for specific values of (x).
It is: 16-20 = -4 which means that the given quadratic expression has no real roots.