Answer: 30 (Dad) & 6 (Son) 2 years later they will be 32 & 8 which equals 40.
a father is 30 years older than his son.in 12 years,the men will be three times as old as his son.find their present ages.
son is 10, father is 33
G = Girl's present age F = Father's present age 4G = F G +7 = 1/2 (F - 12) By substitution: G + 7 = 1/2 (4G - 12); G = 13 By plugging in the value of G = 13; F = 52 The girl is presently 13 and her father is 52.
The father is 40 and his son is 14, a difference of 26 years and their combined ages equal 54.
It is quite simple... Let the present age of the younger brother be x And, present age of elder brother be y x/y=3/4 eqn1 (x+6)/(y+6)=5/6 eqn 2 Solve these equations simultaniously and u'll get the answer. x=3y/4 6x+36=5y+30 18y/4+36=5y+30 18y/4=5y-6 18y=20y-24 -2y=-24 y=12 years , that is the present age of elder brthr x=3(12)/4=9 years , that is the present age of the younger brthr Usama, uxama_17@hotmail.com
There ages are now 5 and 9 respectively because and in 3 years time 2/3 of 12 = 8
Is this a trick question? The age is the sun is approx 4.6 billion years!
Total ages at present = 42 Total ages in 10 years = 52 Fractions then 15/26 x 52 and 11/26 x 52, ie 30 and 22 so ages now 25 and 17
It is 50 years.
a father is 30 years older than his son.in 12 years,the men will be three times as old as his son.find their present ages.
son is 10, father is 33
There is not enough information to find the father, nor his age.The sum of their ages, in y years' time will be 7b + 2y years.
The father is 40 and his son is 14, a difference of 26 years and their combined ages equal 54.
G = Girl's present age F = Father's present age 4G = F G +7 = 1/2 (F - 12) By substitution: G + 7 = 1/2 (4G - 12); G = 13 By plugging in the value of G = 13; F = 52 The girl is presently 13 and her father is 52.
6 years ago, they were 26 and 52.Now they're 32 and 58.
Ages are 25 and 20, so difference = 5 years.
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