90 CM
37.8
The perimeter of a square = side+side+side+side if 160=4xside then the side equals 40
Area = 289 sq cm so length of side = sqrt(289) = 17 cm Then perimeter = 4*side = 4*17 = 68 cm
Perimeter = 24 cm so length of each side = 24/4 = 6 cm and so area = 6 cm * 6 cm = 36 cm2
If a polygon with a perimeter of 30 centimeters has sides with length 6 cm/side, then it has 30 cm / 6 cm per side = 5 sides. So a regular pentagon with a side length of 6 cm has a perimeter of 30 centimeters.
The answer depends on what information you do have: the length of a side, or a diagonal, the area, ... If a side is of length s cm then the perimeter is 4*s cm.
15 cm
perimeter of octagon is 128 cm= 8 * side side of the octagon=128/8=16 cm
To calculate the perimeter of a regular hexagon, you would multiply the length of one side by 6 since a regular hexagon has 6 equal sides. In this case, the side length is 4.8 cm, so the perimeter would be 4.8 cm x 6 = 28.8 cm. Therefore, the perimeter of a regular hexagon with a side length of 4.8 cm is 28.8 cm.
Length + width = 18 cm so length = 12 cm and width = 6 cm. Presumably the length is the common side so the perimeter of the octagon is 8 x 12 = 96 cm. If the width is the common side then the perimeter of the octagon is 8 x 6 = 48 cm
16 cm for each side
7 cm
64 cm
Area of a square = (length of one side)249 cm2 = (length of one side)27 cm = length of one side========================Perimeter of a square = distance all the way around itPerimeter = (4) x (length of one side)Perimeter = (4) x (7 cm) = 28 cm
3 cm x 6 sides = 18 cm perimeter
A regular pentagon with side length 26 cm has a perimeter of 26*5 = 130 cm. The three sides of the quadrilateral sum to 98.6 cm so the fourth side must be 130-98.6 = 31.4 cm.