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The sum of the interior angles of a regular polygon 2340 is How many sides does the polygon have?
15 sides
How many sides does a convex ploygon have if the measures of its interior angles have a sum of 2880?
n is number of sides. Sum of interior angles is 180n - 360, so 180n = 2880 + 360, ie 3240 and n = 3240/180 ie 18.
How many sides does a polygon have if the sum of its interior angles is equal to the sum of its exterior angles?
The sum of the exterior angles of all polygons equals to 360⁰.Since only the sum of the interior angles of all quadrilaterals equals to 360⁰, the polygon must have 4 sides.
What is the sum of a polygon with interior angles and 39 sides?
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 6660 degrees.
What is the Sum of the exterior angles of a 5-gon?
The sum of the exterior angles of a polygon, with any number of sides, is 360 degrees.
How many sides does a polygon have if the sum of its interior angles is 3240 degrees?
20 sides
How many sides does a polygon have when the sum of the measures of its interior angles is 3240?
20
If the sum of the angles of a polygon is 3240 degrees how many sides does it have?
n = (3240 + 360)/180 ie 20
If the sum of the interior angles of a regular polygon is 2880 degrees how many sides does this polygon have?
18 Angles on a straight line = 180 degrees interior angles 2880 + exterior angles 360 = 3240 degrees 3240 divided by 180 = 18 sides Note that the exterior sum of angles of any polygon is always 360 degrees.
What would the total sum of the interior angles be for a polygon with 20 sides?
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 3240 degrees
If the sum of the interior angles of a regular polygon is 3240 degrees how many sides does this polygon have?
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees So (n-2)*180 = 3240 Hence n-2 = 18 so that n = 20.
How many sides does a regular polygon have if the sum of its interior angle measures is 3240?
The formula for the sum of the interior angles for a polygon having n sides = 2n - 4 right angles. 3240 ÷ 90 = 36 right angles : When 2n - 4 = 36 then 2n = 36 + 4 = 40 : n = 20 The regular polygon has 20 sides.
What is the sum of the measures of the interior angles of a 20-gon?
Sum of the angles of a regular polygon = (#sides - 2) * 180. Sum of 20-gon angles = (20-2) * 180 = 3240
What is the sum of each interior angle in a regular 20 sides polygon?
The sum of the interior angles of a regular polygon can be calculated using the formula (n-2) * 180, where n is the number of sides. For a regular 20-sided polygon, the sum of the interior angles would be (20-2) * 180 = 3240 degrees.
How many sides does a polygon have if the interior angles add up to 3240 degrees?
20 sides The relationship between the sum of interior angles and number of sides is (Sum of angles)/180° + 2 3240/180 + 2 = 18 + 2 = 20 This kind of figure is called an icosagon. 20 sides Alternatively you can find it from the formula Sum of the angles of an n-sided polygon = 180(n-2). So solve the following for n: 3240= 180(n-2) n-2=3240/180=18 n=18+2=20
What is the sum of interior angles icosagon?
3240o. The sum of the interior angles of a n sided polygon is sum = (n - 2) x 180o An icosagon has 20 sides, thus the sum of its interior angles is: sum = (20 - 2) x 180o = 3240o
What is the polygon that the sum of the measures of the interior angles is 3240 degrees?
To find the sum of interior angles for any N-sided polygon = N*180° - 360°Solve the equation: N*180° - 360° = 3240°, for N, and N = 20, so a 20 sided polygon will have sum of interior angles = 3240°, and if it is a regular polygon, then each angle = 162°
