If x+y = 3 and y times x = 2 then y = 1.
This gives us the equations: n = xy = yx x != y (Note that for this example, the != stands for not equal to similar to some programming languages.) xy always equals yx due to the communtative property of multiplication. So there are actually an infinite number of answers. Some are given below: 6 = (2)(3) = (3)(2), 2 != 3 12 = (3)(4) = (4)(3), 3 != 4
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
y = 2 (4X2=8) +9 = 17
(2, 1)
Using the discriminant of b^2 -4ac = 0 the value of k works out as -2
Assuming y' is dy/dx, y = x^4/4 + yx^2
y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2
35
2 plus 2 does not equal pie
This gives us the equations: n = xy = yx x != y (Note that for this example, the != stands for not equal to similar to some programming languages.) xy always equals yx due to the communtative property of multiplication. So there are actually an infinite number of answers. Some are given below: 6 = (2)(3) = (3)(2), 2 != 3 12 = (3)(4) = (4)(3), 3 != 4
144
144
X equals 2 :)
Equals 4, Not 32 + 2 equals 4, not 3.No, 2 plus 2 is 4.
2+2=4
What is the solution set for the equations x-y=2 and -x+y=2
x + y = -4x - y = 2x - y = 2x + y - y = 2 + yx = 2 + yx + y = -42 + y + y = -42 + 2y = -42 - 2 + 2y = -4 - 22y = -62y/2 = -6/2y = -3x = 2 + yx = 2 - 3x = -1The solution of the system is (-1, -3)