Assuming y' is dy/dx, y = x^4/4 + yx^2
(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2
(x+y)2
If th equestion meant: (x+y+z)^2The expansion is:(x+y+z)^2= x^2+2xy+y^2+2yz+z^2+2zx
(x+y)2 = x2 + 2xy + y2
xy and yx are identical so you have 2xy = 545 ie xy = 272.5. Possible answers 5 and 54.5, 10.9 and 25 etc
15xy-2xy-7x+x=13xy-6x
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It's an hyperbola equation.
That would be very hard to answer, because it's not. (x + y)2 = x2 + y2 + 2xy
Because 2x+y is addition not multiplication
Y=15/(2c+2x)
(x+y)power 2 -2xy
2xy + 6xy = 8xy
2xy - 4x plus 8y - 16 equals x plus 4 in parentheses multiplied by 2y minus 4 in parentheses. So, the factors are ( x + 4) and ( 2y - 4) .
2xy=2*30*2=120
(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2
(x - y)2 >= 0 since the left hand side is a square. ie x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy