The graphs of y = 5x - 2 and y = x - 2 will have different slopes but with the same y intercepts.
It would be less steep.
you have to first find the derivative of the original function. You then make the derivative equal to zero and solve for x.
If you mean y = x+5 and y = x+9 then both slopes will be parallel but with different y intercepts
An equation of a line (Linear function, first-degree function). It's a line with a slope of 1/3, meaning for every 3 increase in x, increases by 1.
In this case, you'll need to apply the chain rule, first taking the derivative of the tan function, and multiplying by the derivative of 3x: y = tan(3x) ∴ dy/dx = 3sec2(3x)
It would be less steep
Both lines would be parallel to each but the y intercept would change from 5 to 9
It would be less steep.
If you mean y = x+5 changed to y = x+9 then the lines will be parallel to each other but with different y intercepts.
you have to first find the derivative of the original function. You then make the derivative equal to zero and solve for x.
If you mean y = x+5 and y = x+9 then both slopes will be parallel but with different y intercepts
First column, of x values, is the domain of x - whatever that may be. Second column, of function values is always 3.
formula auto-complete
The figures are exactly the same, but every point on the first graph is exactly 13 below the corresponding point on the second one.
Well, if you solve the equation for "y", you have "y" as a function of "x". Or you can do it the other way round; solve for "x", to get "x" as a function of "y" (the first option is more commonly used, though).
An equation of a line (Linear function, first-degree function). It's a line with a slope of 1/3, meaning for every 3 increase in x, increases by 1.
Yes, the function ln(x) where ln is the logarithm to base e.Yes, the function ln(x) where ln is the logarithm to base e.Yes, the function ln(x) where ln is the logarithm to base e.Yes, the function ln(x) where ln is the logarithm to base e.