It depends on how y depends on x.
If x+y = 3 and y times x = 2 then y = 1.
Y = 4/x^2
y=x y=6-x Set the two equations equal to each other to yield a solution: x=6-x 2x=6 x=3 x=3 will satisfy both equations, that is plugging in x=3 will give the same value for y y=(3)=3 y=6-(3)=3
x = y+3 x+2y = 9 => x = 9-2y y+3 = 9-2y 2y+y = 9-3 3y = 6 y = 2 and x = 5
0.6667
x=y
1.5
x=4 y=x+3 y=4+3 y=7
3
6
One simple solution is y = (x + 5/2)*(x - 2)*(x - 3/2) You can expand that into its cubic form, if you wish.
x2 / y = (6)2 /2 = 36/2 = 18
(x, y) = (-3, -3) or (3, 3)
It depends on how y depends on x.
x= z2 - 3
x+y=3 y=3-2x so x+3-2x=3 so x=0 0+y=3 so y=3