This common question is ambiguous and needs more detail. Variations of the answer with explanations are below.
[Literal Sense]
1 is the answer because the actual number '6' (by itself) only occurs once.
[The Digit 6]
20 is the answer because, the digit 6 appears 20 times in this example:
6, 16, 26, 36, 46, 56, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 76, 86, 96
[The Number 6]
10 is the answer.
These would be the numbers in which '6' occurs:
6, 16, 26, 36, 46, 56, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 76, 86, 96
This is because one does not count the digits that represent values other than 6 (i.e. 60, 600, 6000, etc.). So, in this case, the digits with a strikethrough are uncounted. Simply, 6's are only counted in the ones place value.
Whether that's all there is to it, or the 6s keep going on forever, either way it's a rational number.
Area rectangle = Area of Square (s - 2) x 3s = s2 3s2 - 6s =s2 2s2 - 6s =0 s2 - 3s =0 s(s-3) =0 S= 0, S= 3
It's 26,666,666,666,667/10,000,000,000,000 .(If you had said that the 6s go on forever and never end, then it would have been 22/3 or 8/3 .)
It was between 35 and 40 kph...
Let L be the age of Leah, J as the age of John, and S as the age of Sue.Equation 1: S = L - 6Equation 2: J = L + 5Equation 3: L + J = 41Using Equation 3 to get Leah's age:L + J = 41L + (L + 5) = 412L = 41 - 5L = 18Using Equation 2 and substituting L to get John's age:J = L + 5J = 18 + 5J = 23Check using Equation 3, substituting L and J:L + J = 4118 + 23 = 41Using Equation 1 , substituting L to get Sue's age.S = L - 6S = 18 - 6S = 12Sue is 12 years old.Leah is 18 years old.John is 23 years old.
20.
20
there will be 10 6s through the whole thing
You have to find out how many 6s go into 100 evenly so 100/6=16 with a remainder of 4 so you will pass by 16 6s
20
you would pass ten on the way.
20 remember to include 60, 61, 62, 63, 64, 65, 66 ........
None of them. The correct answer is 20. There are 2 sixes in 66.
The answer is 20.6, 16, 26, 36, 46, 56,60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 76,86, 96. It is 20 because 66 is a double 6.
The question doesn't make sense. I suggest ask again and be more specific.
It depends: if you mean 6 as in 60 then 11, if you mean 6 as in 36 then 10 or if you mean 6 as in 6 then 1.
The Answer:Once. However, if you meant the amount of 6s you pass meaning 6 as a digit, then, start by counting the 6s applicable in the ones place. That would be 10. Then, 6 occurs another time when it reaches every single 60s. Thus, (not counting the aready counted 66), there is 9 more. Therefore, there are 19 6s you shall pass.