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∙ 14y agoArea rectangle = Area of Square
(s - 2) x 3s = s2
3s2 - 6s =s2
2s2 - 6s =0
s2 - 3s =0
s(s-3) =0
S= 0, S= 3
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∙ 14y agoThe equation for a rectangle is h(height) x w(width) = area . By manipulating the equation we can show that width=area/length. So 132/12=11. This means the width of the rectangle is 11.
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
The perimeter of a plane figure is the length of its boundary. Thus the perimeter of a rectangle of length L and width W is 2L + 2W. The perimeter of a circle is the length of its circumference.
Call the width of the rectangle x. Call the length of the rectangle x + 2. The area of the rectangle would be the length times the width. We know this is 15 square inches. Set up the equation and solve for x. (x +2)x = 15 x2 + 2x = 15 x2 + 2x - 15 = 0 Factor the quadratic equation: (x - 3)(x + 5) = 0 x = 3 or x = -5 Since length can't be negative, discard the answer -5. If x = 3, then the width is 3 and the length is x + 2 or 5. 5 x 3 = 15 which equals the area.
The quadratic equation of the square is probably x2-5x+6.25 = 0 because its discriminant is equal to zero giving the equation equal roots of x = 5/2 and x = 5/2
2(x + y) = 156 x = 2y Here x = length of rectangle and y = width
area of the rectangle..
length * width
A ruler can be very helpful in that situation.
If you do not know the length or breadth of a rectangle, you cannot know the area. If you do not know the area of a rectangle, you cannot know the length and breadth. To know the length and breadth of a rectangle, you have to know some other contributing factor in the equation. If you don't, measure it!
By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.
There is no "height" of a rectangle, unless it's a rectangular prism. Do you mean the length? If you have the area of the rectangle, the equation should be:A= L x WPlug in the area and the length and solve for the width, or plug in the area the width of the rectangle, and solve for the length.
The equation for a rectangle is h(height) x w(width) = area . By manipulating the equation we can show that width=area/length. So 132/12=11. This means the width of the rectangle is 11.
The area of rectangle is : 896.0
you must know the length of the rectangle as well in order to fill in the equation A=lengthxWidth
The equation is: 4W-3 = L
A = L*B where L is the length of a rectangle, measured in centimetres (say); B is the breadth of the rectangle in cm and A is the area of the rectangle in cm2