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Area rectangle = Area of Square

(s - 2) x 3s = s2

3s2 - 6s =s2

2s2 - 6s =0

s2 - 3s =0

s(s-3) =0

S= 0, S= 3

Q: A rectangle has length triple the side of this square and width two units less than the side of this square Which equation describes this situation if the two areas are equal?

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The equation for a rectangle is h(height) x w(width) = area . By manipulating the equation we can show that width=area/length. So 132/12=11. This means the width of the rectangle is 11.

A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.

The perimeter of a plane figure is the length of its boundary. Thus the perimeter of a rectangle of length L and width W is 2L + 2W. The perimeter of a circle is the length of its circumference.

Call the width of the rectangle x. Call the length of the rectangle x + 2. The area of the rectangle would be the length times the width. We know this is 15 square inches. Set up the equation and solve for x. (x +2)x = 15 x2 + 2x = 15 x2 + 2x - 15 = 0 Factor the quadratic equation: (x - 3)(x + 5) = 0 x = 3 or x = -5 Since length can't be negative, discard the answer -5. If x = 3, then the width is 3 and the length is x + 2 or 5. 5 x 3 = 15 which equals the area.

The quadratic equation of the square is probably x2-5x+6.25 = 0 because its discriminant is equal to zero giving the equation equal roots of x = 5/2 and x = 5/2

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2(x + y) = 156 x = 2y Here x = length of rectangle and y = width

area of the rectangle..

length * width

A ruler can be very helpful in that situation.

If you do not know the length or breadth of a rectangle, you cannot know the area. If you do not know the area of a rectangle, you cannot know the length and breadth. To know the length and breadth of a rectangle, you have to know some other contributing factor in the equation. If you don't, measure it!

By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.

There is no "height" of a rectangle, unless it's a rectangular prism. Do you mean the length? If you have the area of the rectangle, the equation should be:A= L x WPlug in the area and the length and solve for the width, or plug in the area the width of the rectangle, and solve for the length.

The equation for a rectangle is h(height) x w(width) = area . By manipulating the equation we can show that width=area/length. So 132/12=11. This means the width of the rectangle is 11.

The area of rectangle is : 896.0

you must know the length of the rectangle as well in order to fill in the equation A=lengthxWidth

The equation is: 4W-3 = L

A = L*B where L is the length of a rectangle, measured in centimetres (say); B is the breadth of the rectangle in cm and A is the area of the rectangle in cm2