Any line that is parallel to another line will have the same slope. So if line AB's slope is zero and line CD is parallel to AB, then its slope will also be zero. The slope of line CD, when perpendicular to AB, will be infinity. If line AB has a slope of zero that means its just a horizontal line passing some point on the y-axis. A line that is perpendicualr to this one will pass through some point on the x-axis and therefore have an infinite slope.
The answer depends on what and where m, X and O or mX and mO are!
94 The question cannot be answered because it does not specify what mCBD and x are. The answer is 94.
(a x b)^b =ab x b^2 =ab^3
There is NO solution, because there is NO equals sign. However, 5x + 3x add to 8x (simplified) Remember in Algebra 5x means '5' multiplied to 'x' and '3' multiplied to 'x'. The multiplication sign is never shown in algebra.
ab * -b = -ab^-2
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
5.3 = 2x so x = 5.3/2 = 2.65
In math and algebra, a product is the result of multiplication. The product of a x b is ab.
An example of a ballad with an AB-CD rhyme scheme is "Tam Lin," a traditional Scottish ballad. Each stanza in this ballad follows the AB-CD rhyme scheme where the second and fourth lines rhyme with each other.
(CD - ab)^2 = (CD - ab)(CD - ab) = c^2 d^2 - 2abcd + a^2b^2 Try it with say a = 4, b = 3, c = 2 & d = 1: Then CD = 2 and ab = 12 so CD - ab = -10 and squared = 100 c^2 = 4 d^2 = 1 so c^2d^2 = 4 x 1 = 4 a^2 = 16 b^2 = 9 so a^2b^2 = 16 x 9 =144 2abcd = 48 giving 4 - 48 + 144 = 100. Shazam!
Any line that is parallel to another line will have the same slope. So if line AB's slope is zero and line CD is parallel to AB, then its slope will also be zero. The slope of line CD, when perpendicular to AB, will be infinity. If line AB has a slope of zero that means its just a horizontal line passing some point on the y-axis. A line that is perpendicualr to this one will pass through some point on the x-axis and therefore have an infinite slope.
I use the rule that: (a/b)x(c/d)=(ab/cd) and (a/b)divided by(c/d)= (ac/bd) The reason they change is that when you have to find the lowest common factor, you not only have to change the denominator, but also the numerator.
Does length CD touch side AB at a right angle?If so, from pythagoras...(CA)sq = (CD)sq x (0.5x(AB))sqso...CD=sqrt[(CA)sq / (0.5x(AB))sq]sq = squaredsqrt = square-rootput all your known numbers in the bold equation
x-ab=0 x=ab
When multiplying exponents with the same base add them: x^3*x^2 = x^5 When dividing exponents with the same base subtract them: x^3/x^2 = x^1 or x
7