Function "f" depends on "x", and function "g" depends on function "f".
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F(x) = + 1 and G(x) = 3x
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G(F(x)) =~F(x) = and G(x) = 1F(x) = + 1 and G(x) = 3xF(x) = x + 1 and G(x) =orF(x) = 3x and G(x) = + 1-F(x) = x+ 1 and G(x) =G(F(x)) = x4 + 3~F(x) = x and G(x) = x4F(x) = x + 3 and G(x) = x4F(x) = x4 and G(x) = 3orF(x) = x4 and G(x) = x+ 3-It's F(x) =x4 andG(x) = x+ 3G(F(x)) =4sqrt(x)F(x) = sqrt(x) and G(x) = 4x
Given the function g(f(x)) = 2-x, you can find the domain as you would with any other function (i.e. it doesn't matter if it's composite). The output, however, has to be a real number. With this function, the domain is all real numbers. If you graph it, you see that the function is defined across the entire graph, wherever you choose to plot it.
For the function G defined by G(x)=5x+3, find G(2b).