true
true
A composition function, regarding two functions, is when you apply the first function on the second function on an argument. Bear in mind that a single, unaltered function is when you apply said function to an argument; a composition function simply applies the result of an application as an argument to another function. For example, if one function is defined as f(x) = x + 4 and another is defined as g(x) = 2x, the composition of the two (where f is applied to g) is f(g(x)) = 2x + 4. Note that composition is not commutative; that is, f(g(x)) is not necessarily equivalent to g(f(x)), unless if the functions are either the same or inverses of each other, in which case the result will be the argument; f(f-1(x)) = f-1(f(x)) = x.
∫ [f'(x)g(x) - g'(x)f(x)]/g(x)2 dx = f(x)/g(x) + C C is the constant of integration.
Suppose a function f(.) is defined in the following way: f(1) = 3 f(2) = 10 f(3) = 1 We could write this function as the set { (1,3), (2, 10), (3,1) }. The inverse of f(.), let me call it g(.) can be given by: g(3) = 1 g(10) = 2 g(1) = 3
g(x) = x + 3 Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)
Function "f" depends on "x", and function "g" depends on function "f".
true
In the function ( g(f(x)) ), ( f ) is a function that takes ( x ) as input and produces an output used as input for ( g ). Here, ( g ) depends on the output of ( f ), meaning that ( g ) processes the result obtained from ( f(x) ). Consequently, the overall function ( g(f(x)) ) showcases a composition where the behavior of ( g ) is influenced by the behavior of ( f ) in relation to ( x ).
The composite function f of g is also expressed as f(g(x)). In this case, it would be 12(3x), or 36x.
Since g(x) is known, it helps a lot to find f(x). f(g(x)) is a new function composed by substituting x in f with g(x). For example, if g(x) = 2x + 1 and f(g(x)) = 4x2+ 4x + 1 then you you recognize that this is the square of the binomial 2x + 1, so that f(g(x)) = (f o g)(x) = h(x) = (2x + 1)2, meaning that f(x) = x2. if you have a specific example, it will be nice, because there are different ways (based on observation and intuition) to decompose a function and write it as a composite of two other functions.
In the function G(F(x)), F is a function that relies on G, creating a circular dependency where G's output influences F's behavior. Simultaneously, G itself is dependent on the input x, indicating that changes in x will affect G's output. This interdependence can lead to complex relationships and potentially recursive behavior, depending on how F and G are defined. Care must be taken to ensure that such dependencies do not lead to infinite loops or undefined outcomes.
G, A#, B#, C#, D#, E# and Fx (I'm using all scale degrees for this). Fx is F double sharp which means 'F sharp sharp', which is the same as G.
= x
Natural minor: G#, A#, B, C#, D#, E, F#, G# Harmonic minor: G#, A#, B, C#, D#, E, Fx, G# Melodic minor: G#, A#, B, C#, D#, E#, Fx, G#, F#, E, D#, C#, B, A#, G#
no, f(x) = 1 and g(x) = xx are not the same function. The first function maps all values of x to 1. In essence, no matter what x is, the value f(x) will always equal 1. g(x) maps all values of x to the square of the number entered. For example, g(2) = 4 while f(2) = 1. Because the two functions do not have equivalent outputs for the same input, they cannot be the same function.
The composition of two odd functions is an even function. If ( f(x) ) and ( g(x) ) are both odd, then for their composition ( (f \circ g)(x) = f(g(x)) ), we have ( (f \circ g)(-x) = f(g(-x)) = f(-g(x)) = -f(g(x)) = -(f \circ g)(x) ). Thus, ( (f \circ g)(x) ) satisfies the definition of an even function.
f(X)=4x+4 is the exact same thing as y=4x+4. it simply means the function of x is 4x+4. also, any other letter can be used in place of f. f(X)=4x+4 is the same as g(x)=4x+4.