Sum of all three angles is 180 degrees.
p = 36 so q+r = 180-36 = 144 degrees.
Now, q = 5r so 144 = q+r = 5r+r = 6r
so r = 144/6 = 24 and then q = 5r = 5*24=120
Answer: q = 120 deg, r = 24 deg
Let the second angle be x degrees. The first angle would then be x + 24 degrees, and the third angle would be 4x degrees. According to the triangle angle sum theorem, the sum of all three angles in a triangle is 180 degrees. Therefore, you can set up the equation x + (x + 24) + 4x = 180 and solve for x to find the measures of all three angles.
The angle is 160 degrees and it's supplement is 20 degrees.
Nine degrees. Its supplement 171 degrees is ninteen times 9 degrees.
The supplement of an angle x is equal to 180 - x. The measure of an angle that is nine times its supplement can be written as: x = 9(180 - x) You can then solve for the measure of the angle x: x = 1620 - 9x 10x = 1620 x = 162 Therefore, that angle which is nine times its supplement is itself 162 degrees.
Let the first angle be x the second angle be 4x and the third angle be 80+4x+x: x+4x+80+4x+x = 180 Collect like terms: 10x = 180-80 10x = 100 x = 10 Therefore the measure of the second angle is 40 degrees.
The angles are 140 degrees, 20 degrees and 20 degrees that add up to 180 degrees
Let the second angle be x degrees. The first angle would then be x + 24 degrees, and the third angle would be 4x degrees. According to the triangle angle sum theorem, the sum of all three angles in a triangle is 180 degrees. Therefore, you can set up the equation x + (x + 24) + 4x = 180 and solve for x to find the measures of all three angles.
The angle is 160 degrees and it's supplement is 20 degrees.
The two acute angles total 90 degrees. If the larger angle is 4 times the smaller angle, then the smaller angle is 18 degrees and the larger angle is 72 degrees (4 x 18 degrees).
40-degrees 140-degrees
A = 18.1 degrees B = 54.3 degrees C = 107.6 degrees
The vertex angle of an isosceles triangle is the angle opposite the base of the triangle. Therefore, the other two remaining angles of the triangle are congruent. so, in this problem: Let x = m of angle B Let x1 = m of angle C Let 3x + 20 = m of angle A x + x + 3x + 20 = 180 5x + 20 = 180 5x = 160 x = 32 degrees Since angle B and C are congruent, the measure of angle C = 32 degrees.
A triangle with angles that measure 30, 60, and 90 degrees is a special type of right triangle known as a 30-60-90 triangle. In this triangle, the side opposite the 30-degree angle is half the length of the hypotenuse, and the side opposite the 60-degree angle is √3 times the length of the side opposite the 30-degree angle. This relationship is based on the properties of trigonometry and the ratios of the sides in a 30-60-90 triangle.
Both base angles of an Isosceles triangle are by definition the same and, as the internal angles of a triangle must ad up to 180 degrees (again by definition), the the 3rd angle must = 180 - 2 times Y,
An angle whose measure is two times 90 degrees is a 180 degree angle, which is also a straight angle.
Let the measure of the angle be ( x ) degrees. The complementary angle would then be ( 90 - x ) degrees. According to the problem, ( x = 14(90 - x) ). Solving this equation gives ( x = 14 \times 90 / 15 = 84 ) degrees, so the angle measures 84 degrees and its complementary angle measures 6 degrees.
60 degrees