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It is both.
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How do you determine if you are given a set of ordered pairs that represent a function?
A relation is a set of ordered pairs.A function is a relation such that for each element there is one and only one second element.Example:{(1, 2), (4, 3), (6, 1), (5, 2)}This is a function because every ordered pair has a different first element.Example:{(1, 2), (5, 6), (7, 2), (1, 3)}This is a relation but not a function because when the first element is 1, the second element can be either 2 or 3.
How do you state the domain of this relation 5) (2 3) (1 -4) (-3 3) (-1 -2)?
If this is the whole of the function, then the domain is {2, 1, -3, -1}. That set can be put in increasing order if you wish but that is not necessary.
Is this relation afunction (-32)(2-4)(26)(-3-5)(0 3)?
No, it is not a function.
How would you determine from a list of ordered pairs whether it is a function?
When the value of one variable is related to the value of a second variable, we have a relation. A relation is the correspondence between two sets. If x and y are two elements in these sets and if a relation exists between xand y, then we say that x corresponds to y or that y depends on x, and we write x→y. For example the equation y = 2x + 1 shows a relation between x and y. It says that if we take some numbers x multiply each of them by 2 and then add 1, we obtain the corresponding value of y. In this sense, xserves as the input to the relation and y is the output. A function is a special of relation in which each input corresponds to a single (only one) output.Ordered pairs can be used to represent x→y as (x, y).Let determine whether a relation represents a function. For example:1) {(1, 2), (2, 5), (3, 7)}. This relation is a function because there are not ordered pairs with the same firstelement and different second elements. In other words, for different inputs we have different outputs. and the output must verify that when the account is wrong2) {(1, 2), (5, 2), (6, 10)}. This relation is a function because there are not ordered pairs with the same firstelement and different second elements. Even though here we have 2 as the same output of two inputs, 1 and 5, this relation is still a function because it is very important that these inputs, 1 an 5, are different inputs.3) {(1, 2), (1, 4), (3, 5)}. This relation is nota function because there are two ordered pairs, (1, 2) and (1, 4) with the same first element but different secondelements. In other words, for the same inputs we must have the same outputs. of a but
Which link between two elements could you remove from the relation so that it becomes a function?
2 and d or 5 and d 3 and b or 4 and b 2 and d or 3 and b 3 and b or 3 and e
How do you determine if you are given a set of ordered pairs that represent a function?
A relation is a set of ordered pairs.A function is a relation such that for each element there is one and only one second element.Example:{(1, 2), (4, 3), (6, 1), (5, 2)}This is a function because every ordered pair has a different first element.Example:{(1, 2), (5, 6), (7, 2), (1, 3)}This is a relation but not a function because when the first element is 1, the second element can be either 2 or 3.
How do you state the domain of this relation 5) (2 3) (1 -4) (-3 3) (-1 -2)?
If this is the whole of the function, then the domain is {2, 1, -3, -1}. That set can be put in increasing order if you wish but that is not necessary.
How can you tell if a relation of a graph has a function?
A relation is any set of ordered pairs (x, y), such as {(2, 5), (4, 9), (-3, 7), (2, 0)} or {(2, 3), (5, -2)}. A function is a special type of relation in which each x-value is assigned a unique y-value. So in the two examples given above, the first relation is NOT a function because the x-value of 2 is assigned two different y-values: 5 and 0. The second example above is a relation, since each x-value given (i.e., 2 and 5) is only assigned to one y-value (i.e., 3 and -2, respectively). Two additional examples: {(0, 5), (1, 3), (1, 8), (4, -2)} is NOT a function, because the x-value of 1 is assigned to two different y-values. {(0, 3), (1, 4), (3, -2), (4, 7), (5, 0)} is a function, because there is no x-value that is assigned to more than one y-value. When graphed in the Cartesian plane, you can determine if a relation is a function or not by the "vertical line test", which says that if there is any place where a vertical line can be drawn that will pass through the graph more than once, then that relation is NOT a function. But if every vertical line that can possibly be drawn only passes through the relation at most once, then that relation is a function.
Is this relation afunction (-32)(2-4)(26)(-3-5)(0 3)?
No, it is not a function.
Find the domain and range of the relation and state whether or not the relation is a function 1 4 1 5 1 6 1 7?
Any answers?
Is this relation a function{(0, 0), (0, 1), (0, 2), (0, 4), (0, 5)}?
no
How would you determine from a list of ordered pairs whether it is a function?
When the value of one variable is related to the value of a second variable, we have a relation. A relation is the correspondence between two sets. If x and y are two elements in these sets and if a relation exists between xand y, then we say that x corresponds to y or that y depends on x, and we write x→y. For example the equation y = 2x + 1 shows a relation between x and y. It says that if we take some numbers x multiply each of them by 2 and then add 1, we obtain the corresponding value of y. In this sense, xserves as the input to the relation and y is the output. A function is a special of relation in which each input corresponds to a single (only one) output.Ordered pairs can be used to represent x→y as (x, y).Let determine whether a relation represents a function. For example:1) {(1, 2), (2, 5), (3, 7)}. This relation is a function because there are not ordered pairs with the same firstelement and different second elements. In other words, for different inputs we have different outputs. and the output must verify that when the account is wrong2) {(1, 2), (5, 2), (6, 10)}. This relation is a function because there are not ordered pairs with the same firstelement and different second elements. Even though here we have 2 as the same output of two inputs, 1 and 5, this relation is still a function because it is very important that these inputs, 1 an 5, are different inputs.3) {(1, 2), (1, 4), (3, 5)}. This relation is nota function because there are two ordered pairs, (1, 2) and (1, 4) with the same first element but different secondelements. In other words, for the same inputs we must have the same outputs. of a but
What is the relationship between 5 0 4 1 3 2 2 3 4 1 0 5?
The relation ship betwee them that Un+Un+1=5
How did the poet function p(x)x3-2 describe his close relation with function?
5
What is the domain of 1 3 5 5 7 7?
The domain of 1 3 5 5 7 7 can not be given because it is not a function.
Is this a relation (-3 2) (2 -4) (2 6) (-3 -5) (0 -3)?
Yes, but is is not a function because 2 gets mapped to two different values (as does -3).
What are the next two numbers in the sequence 3 3 5 4 4 3 5?
33 5 44 3 55 1 so the next two numbers are 51 there is a relation between 33 and 44 which is 33-44= 11 and a relation between 44 and the guessed number 55 which is 44-55= 11 if we take the numbers 5 and 3 ... 5-3= 2 and between 3 and the guessed number which is 1 .... 3-1= 2 so that proves the result 33 5 44 3 55 1
