Assuming you mean making a true equation using each of the whole numbers 0 through 9 exactly once, and your teacher will let you "cheat" by multiplying: [(3 - 2 - 1) * 4 * 5 * 6 * 7 * 8 * 9 ]= 0
(6◘9)◘4◘6=10 Whats the answer?????
If this is the equation you presented: 9+x=0 then x would have to equal (-9). This is because the negative 9 and the positive 9 cancel out to equal zero. -Owlsrule96
The equation of the circle is: x^2 + y^2 = 81
Points: (3, 2) and (-9, 6) Slope: -1/3 Equation: 3y = -x+9
To be called an "equation", it must have an equal sign.
Given, that 4x + 6 = 6x - 12; then, (6x - 12) - (4x + 6) = 0, 2x - 18 = 0, and 2x = 18. Thus, x = 9. Checking, we substitute 9 for x in the equation: 4(9) + 6= 6(9) - 12; whence, 36 + 6 = 54 - 12, and 42 = 42, which is patently true. What this means is that the original equation is true exactly when x = 9; otherwise, it is false. We call 'x = 9' the solution to the given equation.
9*8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 + 0
Assuming you mean making a true equation using each of the whole numbers 0 through 9 exactly once, and your teacher will let you "cheat" by multiplying: [(3 - 2 - 1) * 4 * 5 * 6 * 7 * 8 * 9 ]= 0
0*1*2*3*4*5*6*7*8*9 = 0
The solution of an equation means the number that the variable must bein order to make the equation a true statement. If the variable has anyother value, then the equation is not true.For example, here's an equation:x - 4 = 2Can 'x' be 5 ? If it is, then 5-4=2. That's not true, so 'x' can't be 5.Can 'x' be 9 ? If it is, then 9-4=2. That's not true, so 'x' can't be 9.Can 'x' be 6 ? If it is, then 6-4=2. That's true. So '6' is the solution to the equation.
(9+3) - (2 +4) = 6
3
(6◘9)◘4◘6=10 Whats the answer?????
Points: (3, 0) and (0, -9) Slope: 3 Equation: y = 3x-9
-3
Assume the question refers to solving the quadratic equation 6x2 +21x - 45 = 0, then :-This equation can be factored 6x2 + 21x - 45 = (6x - 9)(x + 5) = 0This holds true when either 6x - 9 or x + 5 = 0When 6x - 9 = 0 then x = 9/6 = 1.5 : When x + 5 = 0 then x = -5