The square root of 49 is 7, so it is rational.
No because 7 is a rational number
No. The square root of 49 is plus or minus 7, both of which are integers. And integers are rational numbers - whether they are positive or negative.
49 is a rational number
the 4th root of 49 is the square root of the square root of 49 since square root 49 =7 then simplify is square root of 7
The square root of 49 is 7, so it is rational.
sqrt(49)= 7=====quite rational!
sqrt(49)= 7=====quite rational!
The √49 is 7. It is a rational number.
No because 7 is a rational number
The negative square root of 49 is -7. -7 is whole, integer, and rational number. It's not a natural or irrational number.
No. The square root of 49 is plus or minus 7, both of which are integers. And integers are rational numbers - whether they are positive or negative.
No. The square root of 49 is plus or minus 7, both of which are integers. And integers are rational numbers - whether they are positive or negative.
No because 7 squared equals 49 which is a rational number but the square root of 7 is an irrational number
it is a rational number. since it is a perfect square and a non recurring decimal
Yes, it is
Well, for example, the square root of 4 is 2, which is a rational number. As long as the number which is being square rooted is not a square number itself (i.e. 1, 4, 9, 16 etc.), then it will be irrational. So..... the square roots of 49, 100, 196, for example, are all rational numbers (7, 10 and 14 respectively.) They do not have to be integers. The square of of any rational number automatically has a rational square root eg the square root of 77.41792 is 77.4179 . Rational means expressable as a ratio of integers: 77.4179 is 774179/10000 .