You can determine if any number is divisible by nine by adding its digits together: 2 + 1 + 2 +4 = 9 if the result is divisible by 9, then the original number is divisible by 9. In this case, the answer is divisible by 9 so, yes it is (in fact it is 236 x 9).
this # is divisible by 3, 5, and 9 :-) ;-P
The prime factors of 234 are 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, and 234.The prime factorization of 234 is 2 x 3 x 3 x 13. The distinct prime factors of 234 are 2, 3 and 13.1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, 234
Oh, dude, numbers divisible by both 3 and 9 are multiples of the least common multiple of 3 and 9, which is 9. So, any number that is a multiple of 9 is also divisible by 3 and 9. Like, it's just basic math, nothing to lose sleep over.
'121'. 121/3 = 40.3333..... Not divisible. 121/5 any number that does not end in '5' or '0' is not divisible by '5' 121/7 = 17 3/7 Not divisible. 121/9 any number whose digits do not sum to nine is not divisible by '9' ; 1+2+1 = 4
Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.
234 is divisible by: 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117 and 234.
Yes, 234 it is divisible by 9 to give an answer that is a whole number.9 x 30 = 270 = too high9 x 20 = 180 = OKso234 - 180 = 54 which is divisible by 9so9 x 6 = 54so20+6 = 26(and the answer for 234/9 = 26).
For each given number, add the digits. If the sum comes to nine, then it is divisible by '9'. 234 ; 2 + 3 + 4 = 9 So is dividble by '9' 345 ; 3 + 4 + 5 = 12 = 1 + 2 = 3 Not divisible by '9' 567 ; 5 + 6 + 7 = 18 = 1 + 8 = 9 so is divisible by '9'.
123
The factors of 234 are 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, and 234
Oh, isn't that a happy little question! Let's take a look at our numbers here. If we want a number to be divisible by both 2 and 9, it needs to be divisible by both 2 and 9 individually. So, out of the options given, 234 is the number that fits the bill, like a little squirrel finding its cozy tree home for the winter.
234 is even and divisible by three. It has to be divisible by 6.
234 is an even number so it is divisible by 2.
1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, 234
234 ========== or 243
Well - it's an even number - so it is definitely divisible by 2. If you add the digits together, you get the number 9, so it will divide by 3,6 & 9.