Yes, 234 is divisible by 9 because on dividing 234 by 9 we get 26 as quotient and 0 as remainder.
A number is divisible by another number if:
1- Quotient is a whole number
2- Remainder is zero
Yes
You can determine if any number is divisible by nine by adding its digits together: 2 + 1 + 2 +4 = 9 if the result is divisible by 9, then the original number is divisible by 9. In this case, the answer is divisible by 9 so, yes it is (in fact it is 236 x 9).
this # is divisible by 3, 5, and 9 :-) ;-P
The prime factors of 234 are 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, and 234.The prime factorization of 234 is 2 x 3 x 3 x 13. The distinct prime factors of 234 are 2, 3 and 13.1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, 234
27 for one then there's 36, 45, 54, 18 in short, any number divisible by 9 is also divisible by 3
'121'. 121/3 = 40.3333..... Not divisible. 121/5 any number that does not end in '5' or '0' is not divisible by '5' 121/7 = 17 3/7 Not divisible. 121/9 any number whose digits do not sum to nine is not divisible by '9' ; 1+2+1 = 4
Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.
234 is divisible by: 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117 and 234.
Yes, 234 it is divisible by 9 to give an answer that is a whole number.9 x 30 = 270 = too high9 x 20 = 180 = OKso234 - 180 = 54 which is divisible by 9so9 x 6 = 54so20+6 = 26(and the answer for 234/9 = 26).
For each given number, add the digits. If the sum comes to nine, then it is divisible by '9'. 234 ; 2 + 3 + 4 = 9 So is dividble by '9' 345 ; 3 + 4 + 5 = 12 = 1 + 2 = 3 Not divisible by '9' 567 ; 5 + 6 + 7 = 18 = 1 + 8 = 9 so is divisible by '9'.
123
The factors of 234 are 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, and 234
Only 234 is divisible by both 2 and 9.
234 is even and divisible by three. It has to be divisible by 6.
234 is an even number so it is divisible by 2.
234 ========== or 243
1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, 234
Well - it's an even number - so it is definitely divisible by 2. If you add the digits together, you get the number 9, so it will divide by 3,6 & 9.