If you mean 2x -3y = 6 then it is true and so is (3, 0)
Points: (4, -4) and (-2, 0) Slope: -2/3 Equation: y = -2/3x-4/3 or as 3y = -2x-4
Assuming this is part of an equation but missing "= 0" and you want the values of y: (3y - 3)(y - 2) are the factors so y = 1 or 2.
6x - 3y = 12y intercept at x = 0 is y = 4x intercept at y = 0 is x = 2the graph is straight line passing through the two points: (0, 4) and (2, 0)
It works out in its general form as: 3x-4y-6 = 0
This is an equation of a line. There are an infinite number of solutions which are all points on the line. It is a linear equation.
It is not a linear function because it is missing x as the input variable
Yes.
Yes it is
9x^4 -18x^2 + 5=0 Let y be x^2 9y^2-18y+5=0 (3y-5)(3y-1)=0 3y-5=0 or 3y-1=0 3x^2-5=0 3x^2-1=0 x^2=±√5/3 x=±1/√3
If you mean 2x -3y = 6 then it is true and so is (3, 0)
The slope-intercept form of the equation of a line is y = mx + b, wher m = slope and b = y-intercept.2 - 3y + 6x = 0 just solve for y2 - 2 - 3y + 6x - 6x = 0 - 6x - 2-3y = - 6x - 2-3y/-3 = - 6x/-3 - 2/-3y = 2x + 2/3
Points: (0, -2) and (6, 0) Slope: 1/3 Equation of line: 3y = x-6
5
-3X + 3Y = 6 3Y = 3X + 6 Y = X + 2 slope(m) = 1 Y intercept = 2 Another way to find Y intercept is to 0 out X in first equation -3(0) + 3Y = 6 3Y = 6 Y = 2
If you mean: 2x-3y-1 = 0 then it is y = 2/3x-1/3
I am assuming you mean the form Y=MX+C 2x-3y-6=0 2x-6=3y 2/3x-2=y y=2/3x-2 slope =2/3