23 29 31 37 41 43 47 53 . . .
Average = (65 + 41 + 14)/3 = 120/3 = 40
Sue -- 8 Leah -- 14 John -- 19
It is -41.
Sue is 8 years old. Sue (8) + Leah (14) + John (19) = 41 Solve algebraically by stating all ages in terms of Leah's (L) Sue S = L - 6 (Leah = Sue + 6) John J = L + 5 (Leah = John + 8) S + J + L = 41 (L-6) + (L+5) + L = 41 3L -1 = 41 3L = 42 L = 14 S = 8 J = 19
It is 43
23 is less than 41
Greater the divisor is less than 1,so the quotient is greater than the dividend
The prime numbers that are greater than 31 but less than 50 are: 37, 41, 43 and 47.
41, 43, 47.
They are: 41 43 and 47
41, 43, and 47.
41 43 47.
23 29 31 37 41.
31 37 41 43 47.
There are infinitely many of them: 41/97 is one such.
31, 37, 41, 43, and many more.