Sue -- 8
Leah -- 14
John -- 19
8
Sue is 8 years old. Sue (8) + Leah (14) + John (19) = 41 Solve algebraically by stating all ages in terms of Leah's (L) Sue S = L - 6 (Leah = Sue + 6) John J = L + 5 (Leah = John + 8) S + J + L = 41 (L-6) + (L+5) + L = 41 3L -1 = 41 3L = 42 L = 14 S = 8 J = 19
use an equation x=sue x+x+6+x+11=41 -17 -17 3x= 24 /3 /3 x= 8 sue is 8
Let L be the age of Leah, J as the age of John, and S as the age of Sue.Equation 1: S = L - 6Equation 2: J = L + 5Equation 3: L + J = 41Using Equation 3 to get Leah's age:L + J = 41L + (L + 5) = 412L = 41 - 5L = 18Using Equation 2 and substituting L to get John's age:J = L + 5J = 18 + 5J = 23Check using Equation 3, substituting L and J:L + J = 4118 + 23 = 41Using Equation 1 , substituting L to get Sue's age.S = L - 6S = 18 - 6S = 12Sue is 12 years old.Leah is 18 years old.John is 23 years old.
John's price: k = 20 Jenny's price: 10+k = 20 or k = 20-10 => k = 10 Difference in price is 10 pence
8
Sue is 10. Leah is 16 John is 15 Making the combined ages 41.
30 duhh!your a idiot...... its 8
Sue is 8 years old. Sue (8) + Leah (14) + John (19) = 41 Solve algebraically by stating all ages in terms of Leah's (L) Sue S = L - 6 (Leah = Sue + 6) John J = L + 5 (Leah = John + 8) S + J + L = 41 (L-6) + (L+5) + L = 41 3L -1 = 41 3L = 42 L = 14 S = 8 J = 19
use an equation x=sue x+x+6+x+11=41 -17 -17 3x= 24 /3 /3 x= 8 sue is 8
Sue is 14.Leah is 9.John is 18.L = S - 5J = S + 4L + S + J = 41(S - 5) + S + (S + 4) = 413S - 1 = 413S = 42S = 14PROOF: 14 + 9 + 18 = 41
The sum of the three kids ages is 41. So we can say that S+J+L=41 We know that Leah is years older than Sue. So we can write her age as L=S+6. We also know that John is 5 years older than Leah. So we can write his age as J=L+5 Since L=S+6 we can write J as S+6+5 or J=S+11 Now we have all three kids ages as terms of Sue's age. S S+6 S+11 Now we add those together and set them equal to 41. 3S+17=41 3S=24 S=8 Sue is 8 years old.
Let L be the age of Leah, J as the age of John, and S as the age of Sue.Equation 1: S = L - 6Equation 2: J = L + 5Equation 3: L + J = 41Using Equation 3 to get Leah's age:L + J = 41L + (L + 5) = 412L = 41 - 5L = 18Using Equation 2 and substituting L to get John's age:J = L + 5J = 18 + 5J = 23Check using Equation 3, substituting L and J:L + J = 4118 + 23 = 41Using Equation 1 , substituting L to get Sue's age.S = L - 6S = 18 - 6S = 12Sue is 12 years old.Leah is 18 years old.John is 23 years old.
John Leah was born on 1978-08-03.
I heard he is currently single and I believe he is not dating Leah Marsh
are twins but i belive john is older than lenny<3
Leah marsh