Algebraically, yes. Since multiplication is a commutative property, the order in which numbers are multiplied do not change their value. In this problem, both mean that the number 4 is multiplied by an unknown variable, "x". The only exception would be if there were a number that preceeds "x", thereby suggesting that the "x" refers to the actual act of multiplying (e.g., 2 x 4).
It is: 4(6x+x) = 24x+4x => 28x
(4x2 - 13x - 12)/(4x+ 3) = (4x + 3)(x - 4)/(4x + 3) = (4x + 3)(x - 4)/(4x + 3) = x - 4 :)
4*(x + 3) = 4*x + 4*3 = 4x + 12
4X = 16X2 4X - 16X2 = 0 (1 - 4X)4X = 0 ------------------ as you see X = 0 -------- 1 - 4X = 0 - 4X = - 1 X = 1/4 ----------- So, X = 0 and X = 1/4. You check.
4x^4 or 4x*4x*4x*4x A formula would be (x^a)(x^b)= x^a+b x^a) / (x^b)= x^a-b
It is: 4(6x+x) = 24x+4x => 28x
It is: 4(6x+x) = 24x+4x => 28x
(6-4x)(x-2)+3x =6x-12-4x+8x+3x =5x-4
It is equivalent to x + y + 4.
(4x2 - 13x - 12)/(4x+ 3) = (4x + 3)(x - 4)/(4x + 3) = (4x + 3)(x - 4)/(4x + 3) = x - 4 :)
4*(x + 3) = 4*x + 4*3 = 4x + 12
x-intercept of y equals -4x plus 4 y = -4x + 4 0 = -4x + 4 -4 = -4x 1 = x So 1 is the x-intercept
4X = 16X2 4X - 16X2 = 0 (1 - 4X)4X = 0 ------------------ as you see X = 0 -------- 1 - 4X = 0 - 4X = - 1 X = 1/4 ----------- So, X = 0 and X = 1/4. You check.
4x^4 or 4x*4x*4x*4x A formula would be (x^a)(x^b)= x^a+b x^a) / (x^b)= x^a-b
If that's +4x, the answer is (x - 4)(x + 8) If that's -4x, the answer is (x + 4)(x - 8)
y = -4x + 4 x intercept is where y = 0 0 = -4x +4 4x = 4 x = 1
x - 4x + 4 = -3x + 4 which cannot be factorised.