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Algebraically, yes. Since multiplication is a commutative property, the order in which numbers are multiplied do not change their value. In this problem, both mean that the number 4 is multiplied by an unknown variable, "x". The only exception would be if there were a number that preceeds "x", thereby suggesting that the "x" refers to the actual act of multiplying (e.g., 2 x 4).
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What is the an equivalent expression to 4(6x plus x)?
It is: 4(6x+x) = 24x+4x => 28x
What is 4x2-13x-12 divided by 4x plus 3?
(4x2 - 13x - 12)/(4x+ 3) = (4x + 3)(x - 4)/(4x + 3) = (4x + 3)(x - 4)/(4x + 3) = x - 4 :)
What is 4x squared times 4x squared?
When you multiply 4x² by 4x², you multiply the coefficients (4 * 4 = 16) and add the exponents of the variables (x² * x² = x^(2+2) = x⁴). Therefore, the result is 16x⁴.
What is the distributive property to write an expression equivalent to 4(x plus 3)?
4*(x + 3) = 4*x + 4*3 = 4x + 12
How do you solve 4x equals 16x2?
4X = 16X2 4X - 16X2 = 0 (1 - 4X)4X = 0 ------------------ as you see X = 0 -------- 1 - 4X = 0 - 4X = - 1 X = 1/4 ----------- So, X = 0 and X = 1/4. You check.
