If you mean: 9x2-36x+16 then it is not a perfect square because its discriminant is greater than zero
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false, in order to be one 8 would have to be a square number which it is not. So the constant term in the trinomial would need to be 4, 9, 16 etc.
If a trinomial is a perfect square, then the discriminant will equal 0. The discriminant is equal to B^2-4AC. The variables come from the standard form of a quadratic which is Ax^2+Bx+C In this problem, A=81, B=-72, and C=16 so the discriminant is: (-72)^2-4(81)(16)=5,184-5,184=0 so this is a perfect square trinomial. To factor, notice that 81=9^2 and 16=4^2, so 81x^2=(9x)^2. We can then factor the trinomial into (9x+4)(9x-4)
To make the expression y^2 + 8y + c a perfect square trinomial, we need to find the value of c that completes the square. The formula to complete the square is (b/2)^2, where b is the coefficient of the y-term, which is 8 in this case. So, (8/2)^2 = 16. Therefore, the value of c that makes the trinomial a perfect square is 16.
16 is a perfect squarebecause 16 = 4 x 4
The largest perfect square factor of 48 is 16.