Only when a and b have the same sign (or when a or b equals 0). Here are some examples:
|2+4|=|2|+|4|--> |6|=|6|--> 6=6 TRUE
|(-1)+(-3)|=|(-1)|+|(-3)|--> |(-4)|=1+3--> 4=4 TRUE
|3+(-6)|=|3|+|(-6)|--> |(-3)|=3+6--> 3=9 FALSE
what is the absolute value of 5.24
Using the discriminant of b^2 -4ac = 0 the value of k works out as -2
Depends on what the value of B is. It can be written as b+3
(x - a) + (x - a) + (b) = 2 (x - a) + (b) = x - a + x - a + b = 2x - 2a + b
No. If you expand (a + b)2 you get a2 + 2ab + b2. This is not equal to a2 + b2
The expression (a+b) + (a-b) can be rewritten as a + b + a - b = 2a.There is no need to use absolute value.
That depends what the value of a and b are.
|a + b| ≤ |a| + |b|
the absolute value of a over b is not the invers. it is a posative number of a over b. when you see the absolute value, just change it to a posative number. if it is posative, you have your answer.
If a + b + c + d + 80 + 90 = 100, then a + b + c + d = -70.
The absolute value of the sum of two complex numbers is less than or equal to the sum of their absolute values.
b + a + b - a = 2b
1. With boolean algebra, 1 + n is always equal to 1, no matter what the value of n is.
NO! abs(2-2)=0 NOT equal to abs(2)+abs(-2)=4 - The above is technically correct, though the more thorough answer is as follows; no because the absolute value of the sum is LESS THEN OR EQUAL TO the sum of the absolute values. The simple proof the the fact that |A+B|<=|A|+|B| is called the triangular inequality. When A and B (or for that matter an infinite number of them) are both positive (or all) or both negative (or all) then they inequality is actually equal, if however any of the numbers have different signs then any other number, the inequality is less then.
The GCF is the absolute value of B
If a + b = 6, what is the value of 3a + 3b?
what is the absolute value of 5.24