(xa)b = xa*b = xab (xy)a = xaya
No. If you expand (a + b)2 you get a2 + 2ab + b2. This is not equal to a2 + b2
sqrt(a)+sqrt(b) is different from sqrt(a+b) unless a=0 and/or b=0. *sqrt=square root of
You measure the change in the vertical direction (rise) per unit change in the horizontal direction (run). The rate of change is constant between A and B if AB is a straight line. Take any two points, A = (xa, ya) and B = (xb, yb) then the average rate of change, between A and B = (yb- ya)/(xb- xa).
b times b times b = b3 b plus b plus b = 3b
Suppose you have the expression Xa/b. Xa/b is equal to b√(Xa) that is, the bth root of (X to the power a). Equivalently, it is (b√X)a, that is (the bth root of X), raised to the power a.
x to the power a divided by x to the power b = x to the power (a - b), ie xa/xb = xa-b. When a = b, xa/xb = 1 and a - b = 0 so xa-b = x0. Rearranging gives x0 = 1. This is true for ALL non-zero values of x.
If A = (xa, ya) and B = (xb, yb) and xa is not equal to xb, then gradient of AB = (ya - yb)/(xb - xb).If xa = xb then the gradient is undefined.
Any number to the power zero is equal to one. That can be derived from the following index law: xa*xb = xa+b (x not zero) Now let b = 0 so that the above becomes xa*x0 = xa+0 so xa*x0 = xa (since a+0 = a) That is, any number multiplied by x0 is the number itself. That can be true only if x0 is the multiplicative identity, that is, only if x0 = 1.
It is a consequence of the definition of the index laws. xa * xb = xa+b If you put b = 0 in the above equation, then you get xa * x0 = xa+0 But a+0 = a so that the right hand side becomes xa Thus the equation now reads xa * x0 = xa For that to be true for all x, x0 must be the identity element for multiplication. That is x0 = 1 for all x.
This derives from one of the laws of indices which states that, for any x (not = 0), xa * xb = xa+b Put b = 0 Then xa * x0 = xa+0 = xa (because a + 0 = a) But that means that x0 is the multiplicative identity. And since that is unique, and equal to 1, x0 = 1. This is true for all x. Put
The exponent rule for multiplication is xa * xb = xa+b Now, if you put b = 0, then a+b = a so that the above reads: xa * x0 = xa which only works if x0 = 1.
2b
b + a + b - a = 2b
associative
Neither. They are equal.(43)2 is the same as 46 = 4096 ...remember (xa)b = xa*b(23)4 is the same as 212 = 4096
The question is ambiguous: xa+1 * xa+1 = x2(a+1) or (xa + 1)(xa + 1) = x2a + 2xa + 1