Linear
Because power dissipated in rl circuit is given by p= 1/2(Li²)+ i²R which will give a curve and not a linear graph. Secondly the graph is a cosine curve ,with a phase difference between current and voltage. Hence the waveform is not symmetrical to x-axis .
The term "linear line" is redundant; lines are necessarily linear, since linear means in the form of a line.
A system of linear equations is two or more simultaneous linear equations. In mathematics, a system of linear equations (or linear system) is a collection of linear equations involving the same set of variables.
No a linear equation are not the same as a linear function. The linear function is written as Ax+By=C. The linear equation is f{x}=m+b.
linear (A+)
The initial condition is the voltage and/or current existing at the time a mathematical solution begins. Example: what happens when a resistor is connected across a capacitor? well, you say that at t=0 the resistor is connected, then after that the voltage across the capacitor is v0.exp(-t/RC), where v0 is the starting voltage, t is the time, R is the resistance and C is the capacitance. This simple solution needs only one initial condition which is the starting voltage v0 across the capacitor. Linear differential equations are common in electrical engineering and a complete solution of one (such as the example) always requires one or more initial conditions.
non linear
When using the Op-amp we get constant current generation of the linear sweep voltage.
In the graph of voltage vs current, the relationship between voltage and current is linear. This means that as voltage increases, current also increases proportionally.
A capacitor resists a change in voltage (dv/dt = i/c). An inductor resists a change in current (dl/dt = vl). Together, a capacitor and inductor make a tuned circuit. Usually, in a linear power supply, there is a capacitor in parallel with an inductor in series, and often, in a pi filter, another capacitor in parallel. This reduces the peak to peak voltage at the output. It is also possible to put an inductor in series with the rectifier diode, as as to reduce inrush current. In a switching power supply, things are a little bit different. The primary inductor is a current pump, maintaining constant current flow to the load, controlled by the pulse-width oscillator which switches between on-current from source and off-current from schottky diode. The capacitor in this case filters the output, so as to reduce high frequency harmonics.
Because V = I x R or Voltage = Current x Resistance. Since resistance is linear there is a linear relationship between Current and voltage. If you have DC voltage you have DC current and if you have AC Voltage you have AC current. Note that there is a linguistic recognition of this relationship in that the voltage is described in terms of the current.
An inductor is an electrical component, usually a coil, designed to offer a specific value of inductance (measured in henrys). As the operating current of an inductor affects its inductance its inductance value (inductors are not linear devices, due to their hysteresis characteristics) is normally expressed for a specific range of operating currents.
The current vs voltage graph shows that there is a linear relationship between current and voltage in the given circuit. This means that as voltage increases, the current also increases proportionally.
Yes, provided the resistance is constant. If the resistance varies with current, then you have a non-linear circuit
Linear.
Yes, it possible to heat a coil using dc power supply. An inductor resists a change in current, proportional to voltage and inversely proportional to inductance. The equation of an inductor is di/dt = v/L An ideal inductor, if connected to an ideal DC supply, with ideal conductors, would ramp up current in a linear fashion without limit, eventually reaching infinity amperes after infinite time. Since no inductor is ideal, nor is any DC supply, nor is any conductor, the current would reach a maximum based on the capacity of the DC supply and the DC resistance of the inductor and conductors. Since the DC resistance of the inductor is also not zero, this means, by Ohm's law, that the inductor must dissipate some power. That will cause the inductor to heat up.
Inductor is a nonlinear device. since v=L di/dt.