m = dV (d for density (even though greek letter rho should be used))therefore m = (1.0 g/cm3)(5 L)m = (1.0 g/cm3)(5 dm3) (since 1 L = 1 dm3)m = (1.0 g/cm3)(5000 cm3) (since 1 dm3 = 1000 cm3)m = 5000 gm = 5 kg2,000 cm³
-1 multiplied by -1 is 1
When working with exponents there are a couple of rules for 1 to remember. Any number that is brought to the power of “one” will always equal that same number or itself. Secondly one at any power is still one. So for two equal bases to have their product be one, they both can equal one.
one squared equals one.
One to any power is equal to one.
At STP 1 mole of every gas has the volume of 22.4 dm3. (1 dm3 = 1 L)According to previous law, 1 mol - 22.4 dm3 x - 5.68 dm3-------------------------- x = 0.2536 mol1 mol of NO weights 30 g (Ar for N is 14, and Ar for O is 16. Mr(NO) = Ar(N) + Ar(O)), so1 mol - 30 g0.2536 mol - x------------------------------x = 7.6080 gSo the mass of 5.68 L of NO at STP is 7.6080 grams.
98 g per dm3 would be 1 molar - so 49 g would be 0.5 molar , so 4.9 g is 0.05 mol per dm3 or 0.05 mol.dm-3
right i dont know this 4 sure but because u want a 0.1 mol/dm3 and u only need 100cm3 u will need 0.01mols of copper sulfate to dilute in 100cm3. soo now u have a solution that is 0.01mols per 100cm3 or 0.1 mols per 1000cm3 (dm3)
The reaction : Mg + O2-----------> MgO The balanced reaction : 2 Mg + O2-----------> 2 MgO that is 2 moles of Mg reacts with one mole of oxygen gas. moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol. Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol If the gas is at standard temperature and pressure, then Volume of 1 mol of O2 gas = 22.4 dm3 Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3 the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)
One litre is equal to one cubic decimetre.
1 ml is stand for one milliliter, which is 1/1000 of one liter. Mathematically, one liter is 1 dm3 so 1/1000 of one liter equal 1/1000 of 1 dm3, then 1ml equal 1cm3. cc is stand for cubic centimeter, it's refers to the volume of a cubic which have 1cm edge so it's volume is 1cm3. So we can see the problem is clearly solved, 1cc equal 1ml.
1 mol = 1 mol
1 liter is 1 dm3
which is gigger dm3 or mL
22,4 L is the molar volume. 1 mol of oxygen has 32 g and and 6,022140857.10e23 molecules.
The molar volume, symbol Vm,[1] is the volume occupied by one mole of a substance (chemical element or chemical compound) at a given temperature and pressure. It is equal to the molar mass (M) divided by the mass density (ρ). It has the SI unit cubic metres per mole (m3/mol),[1] although it is more practical to use the units cubic decimetres per mole (dm3/mol) for gases and cubic centimetres per mole (cm3/mol) for liquids and solids.
In room condition the volume is 24dm3 So convert 500cm3 to dm3 1 dm3 equals 1000cm3 x dm3 equals 500cm3 500รท1000=0.5dm3 6.02ร10^23 molecules of O2 equals 24 dm3 xmolecules equals 0.5dm3 0.5ร6.02 ร10^23 รท24= 1.25 ร10^22