No.
m = dV (d for density (even though greek letter rho should be used))therefore m = (1.0 g/cm3)(5 L)m = (1.0 g/cm3)(5 dm3) (since 1 L = 1 dm3)m = (1.0 g/cm3)(5000 cm3) (since 1 dm3 = 1000 cm3)m = 5000 gm = 5 kg2,000 cm³
-1 multiplied by -1 is 1
When working with exponents there are a couple of rules for 1 to remember. Any number that is brought to the power of “one” will always equal that same number or itself. Secondly one at any power is still one. So for two equal bases to have their product be one, they both can equal one.
one squared equals one.
One to any power is equal to one.
98 g per dm3 would be 1 molar - so 49 g would be 0.5 molar , so 4.9 g is 0.05 mol per dm3 or 0.05 mol.dm-3
right i dont know this 4 sure but because u want a 0.1 mol/dm3 and u only need 100cm3 u will need 0.01mols of copper sulfate to dilute in 100cm3. soo now u have a solution that is 0.01mols per 100cm3 or 0.1 mols per 1000cm3 (dm3)
The reaction : Mg + O2-----------> MgO The balanced reaction : 2 Mg + O2-----------> 2 MgO that is 2 moles of Mg reacts with one mole of oxygen gas. moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol. Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol If the gas is at standard temperature and pressure, then Volume of 1 mol of O2 gas = 22.4 dm3 Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3 the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)
1 ml is stand for one milliliter, which is 1/1000 of one liter. Mathematically, one liter is 1 dm3 so 1/1000 of one liter equal 1/1000 of 1 dm3, then 1ml equal 1cm3. cc is stand for cubic centimeter, it's refers to the volume of a cubic which have 1cm edge so it's volume is 1cm3. So we can see the problem is clearly solved, 1cc equal 1ml.
1 mol is the equivalent of 24,000cm3 So, Moles = Value is cm3 (divided by) 24,000
At STP 1 mole of every gas has the volume of 22.4 dm3. (1 dm3 = 1 L)According to previous law, 1 mol - 22.4 dm3 x - 5.68 dm3-------------------------- x = 0.2536 mol1 mol of NO weights 30 g (Ar for N is 14, and Ar for O is 16. Mr(NO) = Ar(N) + Ar(O)), so1 mol - 30 g0.2536 mol - x------------------------------x = 7.6080 gSo the mass of 5.68 L of NO at STP is 7.6080 grams.
1 dm3 is equal to 1 liter. They are equivalent volumes, with 1 liter being the same as 1 cubic decimeter.
2.2 mol water = 2.2 (mol) * 18 (g/mol) water = 39.6 (mol*g/mol) = 40 g18 g/mol = mol mass of H2O = 2*H + 1*O = (2*1 + 16) g/mol
1 liter is 1 dm3
Well, honey, 1 dm3 is bigger than 1 mL. A decimeter is 10 times bigger than a centimeter, so a cubic decimeter (dm3) is equal to 1000 milliliters (mL). So, in this case, size does matter, and 1 dm3 takes the cake.
1 mol = 1 mol
22,4 L is the molar volume. 1 mol of oxygen has 32 g and and 6,022140857.10e23 molecules.