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How do I convert the enthalpy of vaporization of water in joules per gram from kiloJoules per mole?
To convert the enthalpy of vaporization of water from kJ/mol to J/g, you need to divide the given value in kJ/mol by the molar mass of water (18 g/mol). This will give you the enthalpy of vaporization in J/g.
How much joules are gained by water during evaporation?
It takes 333.51 or 334 joules to evaporate 1 gram of H2O.
How many grams of water are needed to react with 0.373 mol of ethylene?
To react with 0.373 mol of ethylene (C2H4), you need an equal number of moles of water (H2O) based on the balanced chemical equation: C2H4 + H2O → C2H5OH This means you need 0.373 mol of water to react with 0.373 mol of ethylene. To convert moles to grams, you would multiply 0.373 mol by the molar mass of water (18.015 g/mol) to get the grams needed.
How do you convert 2lb mol of C3H8 to gram?
To convert 2 lb mol of C3H8 to grams, you need to first determine the molar mass of C3H8 (propane) which is approximately 44.1 g/mol. Then, you can multiply the number of moles (2 lb mol) by the molar mass to get the mass in grams. So, 2 lb mol of C3H8 is equal to 2 lb mol * 44.1 g/mol = 88.2 g.
How many grams are in 6.3 moles of BH3?
6.3(mol) * 13.83 (g·mol−1)= 87.1 gram BH3
