Q: Is the area of a trapezoid equal to the products of the height and the length of the midsegment?

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The area of a trapezoid is equal to the height, multiplied by the average of the two widths.

Work out each figure separately then add them together: Area of a trapezoid = 0.5*(sum of parallel bases)*height Area of a rectangle = length*height

height*length*width = volume Divide both sides by length*width to find the height: height = volume divided by length*width

volume = length*height*width Rearrange the formula: length = volume/height*width

trapezoid

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No, the length of the midsegment of a trapezoid is equal to the average of the lengths of the bases. The sum of the lengths of the bases would typically yield a longer length than the midsegment.

You must first know the lengths of the top and bottom of the trapezoid. At this point, you must average those lengths and that is your midsegment length.

You must first know the lengths of the top and bottom of the trapezoid. At this point, you must average those lengths and that is your midsegment length.

It is the average of the bases.

Yes

It is 20 units.

It is (7 + 15)/2 = 11 units of length.

you just take the length of it's midsegment and multiply it by its height to find area. to find it's perimeter, just add the measures of it's sides

Yes. The midsection is equal to the average of the two bases.

The Trapezoid midsegment conjecture- the midsegment of a trapezoid is parallel to the bases and is equal to the length to the average of the lengths of the bases. This is Some what Algebra....... what you do is take your length 90 and midsegment 85 into a prob like this (90+X)/2=85 times by two on both sides to cancel out the two. after that you end up with 90+X=85 next you have to "isolate" the X by subtracting 90 from both sides you would get 90+X=85 -90 -90 to get X= -5 the other side would be -5 so it doesnt work to check it plug the number back into the equation (90+-5)/2=85

A midsegment of a triangle is parallel to the side of the triangle, and it's length is half the length of that side

The length of a midsegment is half that of the parallel side of the triangle; assuming the midsegment is parallel to the [given] base, then its length is 27 ÷ 2 = 13.5 units.