That depends! The identity operator must map something from a space X to a space Y. This mapping might be continuous - which is the case if the identify operator is bounded - or discontinuous - if the identity operator is unbounded.
No it is NOT always bounded. Here is an example of an unbounded one. 1. 2x-y>-2 2. 4x+y
Assuming the domain is unbounded, the linear function continues to be a linear function to its end.
What is the area bounded by the graph of the function f(x)=1-e^-x over the interval [-1, 2]?
Surely, you should check the value of the function at the boundaries of the region first. Rest depends on what the function is.
The inverse of the inverse is the original function, so that the product of the two functions is equivalent to the identity function on the appropriate domain. The domain of a function is the range of the inverse function. The range of a function is the domain of the inverse function.
No. y = 1/x is continuous but unbounded.
bounded signal
Bounded media are those that use cables for transmitting electricity or light; unbounded media does not require cabling and includes satellite, microwave and radio transmission. Wireless connections, including 802.11b and 802.11g, are examples of unbounded media. Today, bounded media continue to be more common than unbounded.
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I believe the maximum would be two - one when the independent variable tends toward minus infinity, and one when it tends toward plus infinity. Unbounded functions can have lots of asymptotes; for example the periodic tangent function.
No, a measurable function may have a finite number of discontinuities (for the Riemann measure), or a countably infinite number of discontinuities (for the Lebesgue measure). It should also be bounded (have some upper and lower bound, or limit, in the domain that is being measured), to be measureable. At least, some unbounded functions are not measurable.No, a measurable function may have a finite number of discontinuities (for the Riemann measure), or a countably infinite number of discontinuities (for the Lebesgue measure). It should also be bounded (have some upper and lower bound, or limit, in the domain that is being measured), to be measureable. At least, some unbounded functions are not measurable.No, a measurable function may have a finite number of discontinuities (for the Riemann measure), or a countably infinite number of discontinuities (for the Lebesgue measure). It should also be bounded (have some upper and lower bound, or limit, in the domain that is being measured), to be measureable. At least, some unbounded functions are not measurable.No, a measurable function may have a finite number of discontinuities (for the Riemann measure), or a countably infinite number of discontinuities (for the Lebesgue measure). It should also be bounded (have some upper and lower bound, or limit, in the domain that is being measured), to be measureable. At least, some unbounded functions are not measurable.
No it is NOT always bounded. Here is an example of an unbounded one. 1. 2x-y>-2 2. 4x+y
Assuming the domain is unbounded, the linear function continues to be a linear function to its end.
A set of numbers is bounded if there exist two numbers x and y (with x ≤ y)such that for every member of the set, x ≤ a ≤ y. A set is unbounded if one or both of x and y is infinite. Similar definitions apply for sets in more than 1 dimension.
A bounded array is an array data structure with a fixed size or capacity. It has a predetermined maximum number of elements that it can hold, and attempting to exceed this limit will result in an error or exception. This can be beneficial for memory management and preventing buffer overflows.
NO
The graphical method for solving LPP in two unknowns is as follows: 1)Graph the feasible region. 2)Compute the coordinates of the corner points. 3)Substitute the coordinates of the corner points into the objective function to see which gives the optimal value. 4)If the feasible region is bounded,this method can be misleading:optimal solutions always exist when the feasible region is bounded,but may or may not exist when the feasible region is unbounded.